Solution #789
Solution #789
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Great job on the pull request! While there are a few minor improvements suggested, such as using os.makedirs(new_dir, exist_ok=True) for directory creation and adopting more descriptive variable names, these do not impact the core functionality of your code. Keep up the good work and consider these suggestions for future enhancements! 😊
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| def move_file(command: str) -> None: | ||
| file_name = command.split()[1] |
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Consider using a more descriptive variable name instead of file_name to better convey its purpose, as per the checklist item: 'Use descriptive and correct variable names.'
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| def move_file(command: str) -> None: | ||
| file_name = command.split()[1] | ||
| new_path = command.split()[2] |
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Consider using a more descriptive variable name instead of new_path to better convey its purpose, as per the checklist item: 'Use descriptive and correct variable names.'
| def move_file(command: str) -> None: | ||
| file_name = command.split()[1] | ||
| new_path = command.split()[2] | ||
| path_list = new_path.split("/") |
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Instead of splitting the path manually, use os.path.join to concatenate parts of the path. This ensures cross-platform compatibility, as per the checklist item: 'Use os.path.join to concatenate parts of the path.'
| if len(path_list) > 1: | ||
| new_dir = os.path.dirname(new_path) | ||
| if not os.path.exists(new_dir): | ||
| os.makedirs(new_dir) |
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Be cautious when using os.makedirs to create directories, as attempting to create a directory that already exists will lead to an error. Consider using os.makedirs(new_dir, exist_ok=True) to avoid this issue, as per the checklist item: 'Notice that if you will try to create the directory already exists then it will lead to an error.'
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