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free() pointer to arrow binary in Python #1273
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is there any case where
is_arrow && is_delete
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e.g. should this match above
if (is_arrow && !is_delete) {
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There shouldn't be any - remove only takes a list of pkeys, but this whole conditional block is kind of messy. I'll take a look and fix.
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This logic is incorrect, but so is the fix suggestion - there should be (or will need to be) one case, for
remove()
... when we get around to fixing this API method generally ...