[이지민] - 모음사전, 카펫, 반지, 몬스터 트럭, 필터 #3
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jeeminimini
changed the title
soopeach
reviewed
Sep 18, 2022
Comment on lines
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| fun order(word: String): Int { | ||
| val list = arrayListOf("A", "E", "I", "O", "U", "") | ||
| var total = mutableSetOf<String>() | ||
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| for (x1 in list) { | ||
| for (x2 in list) { | ||
| for (x3 in list) { | ||
| for (x4 in list) { | ||
| for (x5 in list) { | ||
| for (x6 in list) { | ||
| val newWord = x1 + x2 + x3 + x4 + x5 + x6 | ||
| total.add(newWord) | ||
| } | ||
| } | ||
| } | ||
| } | ||
| } | ||
| } | ||
| val sortedTotal = total.filter { it.length < 6 }.sorted() | ||
| //println(sortedTotal) | ||
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| return sortedTotal.indexOf(word) | ||
| } | ||
| } |
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빈 칸까지 쳐서 for문으로 문자열 만들면 모든 경우를 구할 수 있다는 걸 생각 못했는데 이렇게 하면 되는구나 했어요!
| val parking = arrayListOf<ArrayList<String>>() | ||
| for (i in 0 until x) { | ||
| parking.add( | ||
| readLine()!!.split("").drop(1).dropLast(1) |
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readLine()!! 대신 readln() 을 사용하면 좋을 것 같아요
요기 한번 보셔도 좋을 것 같습니다
jhg3410
reviewed
Sep 18, 2022
| fourParking.clear() | ||
| continue | ||
| } | ||
| when (fourParking.count { it.contains("X") }) { |
| val num = readLine()?.toInt() | ||
| var rings = arrayListOf<String>() | ||
| var sum = 0 | ||
| for (i in 0 until num!!) { |
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전 num 변수처럼 다음 입력의 개수를 표시하는 친구는 repeat(readln().toInt()) {} 이렇게 사용해요!!
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num의 non-null처리를 19라인에서 ?: 연산자로 하면 !!를 안 쓸 수 있을 것 같아요!
Comment on lines
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| for (i in 1..sqrt(yellow.toDouble()).toInt()) { | ||
| if (yellow % i == 0) { | ||
| if (brown == (i + 2) * 2 + (yellow / i) * 2) { | ||
| return intArrayOf(i + 2, yellow / i + 2) |
soopeach
reviewed
Sep 18, 2022
Comment on lines
+20
to
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| val pixel = arrayListOf<ArrayList<Int>>() | ||
| for (i in 0 until x) { | ||
| pixel.add(readLine()!!.trim().split(" ").map { it.toInt() } | ||
| as ArrayList<Int>) |
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pixel을 arrayListOf<MutableList<Int>>()로 사용하시면 22번째에서 입력받은 값(readLine()!! ~~)을 별도로 as ArrayList로 캐스팅하는 대신, toMutableList()로 간단히 형변환을 해줄 수 있어요!!
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📌 from issue #1 📌
📋문제 목록📋
📝메모
NubmerFormat 에러
array에 특정 값이 포함되어있는 개수 구하기
배열.count { it.contains(찾고자 하는 값) }IntArray 출력하기