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problem: new problem solution - 226 . Invert Binary Tree
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problems/algorithms/invertBinaryTree/InvertBinaryTree.test.ts
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// Source : https://leetcode.com/problems/invert-binary-tree/ | ||
// Author : Francisco Tomas | ||
// Date : 2023-11-22 | ||
|
||
import { invertTree, NodeTree } from "./InvertBinaryTree"; | ||
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describe("invertTree", () => { | ||
test("invert empty binary tree", () => { | ||
const result = invertTree(null); | ||
expect(result).toBe(null); | ||
}); | ||
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test("invert binary tree with few elements", () => { | ||
const result = invertTree( | ||
new NodeTree(2, new NodeTree(1, null, null), new NodeTree(3, null, null)), | ||
); | ||
expect(result).toStrictEqual( | ||
new NodeTree(2, new NodeTree(3, null, null), new NodeTree(1, null, null)), | ||
); | ||
}); | ||
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||
test("invert slighty bigger binary tree", () => { | ||
const result = invertTree( | ||
new NodeTree( | ||
4, | ||
new NodeTree( | ||
2, | ||
new NodeTree(1, null, null), | ||
new NodeTree(3, null, null), | ||
), | ||
new NodeTree( | ||
7, | ||
new NodeTree(6, null, null), | ||
new NodeTree(9, null, null), | ||
), | ||
), | ||
); | ||
|
||
expect(result).toStrictEqual( | ||
new NodeTree( | ||
4, | ||
new NodeTree( | ||
7, | ||
new NodeTree(9, null, null), | ||
new NodeTree(6, null, null), | ||
), | ||
new NodeTree( | ||
2, | ||
new NodeTree(3, null, null), | ||
new NodeTree(1, null, null), | ||
), | ||
), | ||
); | ||
}); | ||
}); |
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// Source : https://leetcode.com/problems/invert-binary-tree/ | ||
// Author : Francisco Tomas | ||
// Date : 2023-11-22 | ||
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/***************************************************************************************************** | ||
* | ||
* Given the root of a binary tree, invert the tree, and return its root. | ||
* | ||
* Example 1: | ||
* | ||
* Input: root = [4,2,7,1,3,6,9] | ||
* Output: [4,7,2,9,6,3,1] | ||
* | ||
* Example 2: | ||
* | ||
* Input: root = [2,1,3] | ||
* Output: [2,3,1] | ||
* | ||
* Example 3: | ||
* | ||
* Input: root = [] | ||
* Output: [] | ||
* | ||
* Constraints: | ||
* | ||
* The number of nodes in the tree is in the range [0, 100]. | ||
* -100 <= Node.val <= 100 | ||
******************************************************************************************************/ | ||
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type BT = NodeTree | null; | ||
export class NodeTree { | ||
val: number; | ||
left: BT; | ||
right: BT; | ||
constructor(val?: number, left?: BT, right?: BT) { | ||
this.val = val ?? 0; | ||
this.left = left === undefined ? null : left; | ||
this.right = right === undefined ? null : right; | ||
} | ||
} | ||
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/** | ||
* BT -> BT | ||
* given the root of a binary tree, invert the tree, and return its root | ||
* Stub: | ||
function invertTree(root: BT): BT {return null} | ||
* Tests: | ||
* I: root = [4,2,7,1,3,6,9] -> O: [4,7,2,9,6,3,1] | ||
* I: root = [2,1,3] -> O: [2,3,1] | ||
* I: root = [] -> O: [] | ||
* Template: | ||
function invertTree(root: BT): BT { | ||
if (root === null) {return null} | ||
else { | ||
return (... root.val | ||
(invertTree(root.left)) | ||
(invertTree(root.right))) | ||
} | ||
} | ||
* CONSTRAINTS: | ||
* - The number of nodes in the tree is in the range [0, 100]. | ||
* - -100 <= Node.val <= 100 | ||
*/ | ||
export function invertTree(root: BT): BT { | ||
if (root === null) { | ||
return null; | ||
} else { | ||
return new NodeTree( | ||
root.val, | ||
invertTree(root.right), | ||
invertTree(root.left), | ||
); | ||
} | ||
} |