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Be more direct about borrow contract #59663
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r? @dtolnay (rust_highfive has picked a reviewer for you, use r? to override) |
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Thanks, this is a useful distinction.
@bors r+ rollup |
📌 Commit 1cfed0d has been approved by |
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Be more direct about borrow contract I always was confused by the difference between Borrow and AsRef, despite the fact that I've read all available docs at least a dozen of times. I finally grokked the difference between the two when I realized the Borrow invariant: > If you implement Borrow, you **must** make sure that Eq, Ord and Hash implementations are equivalent for borrowed and owned data My problem was that this invariant is not stated explicitly in documentation, and instead some vague and philosophical notions are used. So I suggest to mention the requirements of `Borrow` very explicitly: instead of "use Borrow when X and use AsRef when Y", let's phrase this as `Borrow` differs from `AsRef` in `W`, so that's why `Borrow` is for `X` and `AsRef` is for `Y`. Note that this change could be seen as tightening contract of the Borrow. Let's say Alice has written the following code: ```rust #[derive(PartialEq, Eq, Hash, PartialOrd, Ord)] struct Person { first_name: String, last_name: String, } impl Borrow<str> for Person { fn borrow(&self) -> &str { self.first_name.as_str() } } ``` Now Bob uses this `Person` struct, puts it into `HashMap` and tries to look it up using `&str` for the first name. Bob's code naturally fails. The question is, who is to blame: Alice, who has written the impl, or Bob, who uses the HashMap. If I read the current docs literally, I would say that `Bob` is to blame: `Eq` and `Hash` bounds appear on HashMap, so it is the HashMap which requires that they are consistent. By using a type for which the `Borrow` impl does not yield well-behaved `Eq`, Bob is violating contract of HashMap. If, as this PR proposes, we unconditionally require that Eq & friends for borrow should be valid, then the blame shifts to Alice, which I think is more reasonable. closes rust-lang#44868
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Be more direct about borrow contract I always was confused by the difference between Borrow and AsRef, despite the fact that I've read all available docs at least a dozen of times. I finally grokked the difference between the two when I realized the Borrow invariant: > If you implement Borrow, you **must** make sure that Eq, Ord and Hash implementations are equivalent for borrowed and owned data My problem was that this invariant is not stated explicitly in documentation, and instead some vague and philosophical notions are used. So I suggest to mention the requirements of `Borrow` very explicitly: instead of "use Borrow when X and use AsRef when Y", let's phrase this as `Borrow` differs from `AsRef` in `W`, so that's why `Borrow` is for `X` and `AsRef` is for `Y`. Note that this change could be seen as tightening contract of the Borrow. Let's say Alice has written the following code: ```rust #[derive(PartialEq, Eq, Hash, PartialOrd, Ord)] struct Person { first_name: String, last_name: String, } impl Borrow<str> for Person { fn borrow(&self) -> &str { self.first_name.as_str() } } ``` Now Bob uses this `Person` struct, puts it into `HashMap` and tries to look it up using `&str` for the first name. Bob's code naturally fails. The question is, who is to blame: Alice, who has written the impl, or Bob, who uses the HashMap. If I read the current docs literally, I would say that `Bob` is to blame: `Eq` and `Hash` bounds appear on HashMap, so it is the HashMap which requires that they are consistent. By using a type for which the `Borrow` impl does not yield well-behaved `Eq`, Bob is violating contract of HashMap. If, as this PR proposes, we unconditionally require that Eq & friends for borrow should be valid, then the blame shifts to Alice, which I think is more reasonable. closes rust-lang#44868
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Be more direct about borrow contract I always was confused by the difference between Borrow and AsRef, despite the fact that I've read all available docs at least a dozen of times. I finally grokked the difference between the two when I realized the Borrow invariant: > If you implement Borrow, you **must** make sure that Eq, Ord and Hash implementations are equivalent for borrowed and owned data My problem was that this invariant is not stated explicitly in documentation, and instead some vague and philosophical notions are used. So I suggest to mention the requirements of `Borrow` very explicitly: instead of "use Borrow when X and use AsRef when Y", let's phrase this as `Borrow` differs from `AsRef` in `W`, so that's why `Borrow` is for `X` and `AsRef` is for `Y`. Note that this change could be seen as tightening contract of the Borrow. Let's say Alice has written the following code: ```rust #[derive(PartialEq, Eq, Hash, PartialOrd, Ord)] struct Person { first_name: String, last_name: String, } impl Borrow<str> for Person { fn borrow(&self) -> &str { self.first_name.as_str() } } ``` Now Bob uses this `Person` struct, puts it into `HashMap` and tries to look it up using `&str` for the first name. Bob's code naturally fails. The question is, who is to blame: Alice, who has written the impl, or Bob, who uses the HashMap. If I read the current docs literally, I would say that `Bob` is to blame: `Eq` and `Hash` bounds appear on HashMap, so it is the HashMap which requires that they are consistent. By using a type for which the `Borrow` impl does not yield well-behaved `Eq`, Bob is violating contract of HashMap. If, as this PR proposes, we unconditionally require that Eq & friends for borrow should be valid, then the blame shifts to Alice, which I think is more reasonable. closes rust-lang#44868
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Rollup of 6 pull requests Successful merges: - #59316 (Internal lints take 2) - #59663 (Be more direct about borrow contract) - #59664 (Updated the documentation of spin_loop and spin_loop_hint) - #59666 (Updated the environment description in rustc.) - #59669 (Reduce repetition in librustc(_lint) wrt. impl LintPass by using macros) - #59677 (rustfix coverage: Skip UI tests with non-json error-format) Failed merges: r? @ghost
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I always was confused by the difference between Borrow and AsRef, despite the fact that I've read all available docs at least a dozen of times.
I finally grokked the difference between the two when I realized the Borrow invariant:
My problem was that this invariant is not stated explicitly in documentation, and instead some vague and philosophical notions are used.
So I suggest to mention the requirements of
Borrow
very explicitly: instead of "use Borrow when X and use AsRef when Y", let's phrase this asBorrow
differs fromAsRef
inW
, so that's whyBorrow
is forX
andAsRef
is forY
.Note that this change could be seen as tightening contract of the Borrow. Let's say Alice has written the following code:
Now Bob uses this
Person
struct, puts it intoHashMap
and tries to look it up using&str
for the first name. Bob's code naturally fails.The question is, who is to blame: Alice, who has written the impl, or Bob, who uses the HashMap. If I read the current docs literally, I would say that
Bob
is to blame:Eq
andHash
bounds appear on HashMap, so it is the HashMap which requires that they are consistent. By using a type for which theBorrow
impl does not yield well-behavedEq
, Bob is violating contract of HashMap.If, as this PR proposes, we unconditionally require that Eq & friends for borrow should be valid, then the blame shifts to Alice, which I think is more reasonable.
closes #44868