I opened up the issues section seeing as some people seem to use this. I'd advise against using this now. This solution was written for a specific time in DHTML land and browsers/CSS/HTML have evolved past this. The future (I think) - for this kind of situation - is using the shadow dom.
Inject and Isolate a specific version of jQuery into the page and use it in a non-conflicting way.
Let's say you're building a widget intended to be embedded within some arbitrary html which you have no control over. Furthermore, let's assume the page which our widget will be installed in either has an older jQuery version than the one you want or it has no jQuery at all. On top of that, you want to use some plugins you made/downloaded that all hook onto the jQuery and $ namespaces without having to rewrite them entirely.... This haphazard of a hack flavoured javascript Helps you do that.
Of course, you cant use this right out of the box depending on the size and distribution of your project but I will try to document the 3 public methods and give a tiny theoretical application of this approach.
/*
jQQ.setup([aVersionString]);
Loads a copy of jquery from google CDN (you can pass in a version string
see: http://code.google.com/apis/libraries/devguide.html#jquery for supported version strings.
*/
jQQ.setup('1.4.2');
/*
jQQ.isolate([aFunction]);
Runs your function whenever the quarantine is ready. The function signature MUST have at least one argument, a jQuery placeholder.
*/
jQQ.isolate(function($){
// $ here is our injected version.
$.fn.myplugin = {
desc: "A magic little plugin that exists only within the confines of quarantine"
};
});
jQQ.isolate(function($){
// Isolate callbacks are executed in order of addition
$(document.body).myplugin();
});
// note: current design makes it that if your callback signature has n arguments it will be passed n times the newly loaded jQuery
// (each argument == jquery)
jQQ.isolate(function(jQuery,$){
// true
return (jQuery === $ && !arguments[2]);
});
jQQ.isolate(function(jQuery,$,another){
// false, because function signature has 3 arguments, the last one is the same as the others.
return (jQuery === $ && !arguments[2]);
});
So basically, figure it out :P
(The MIT License)
Copyright (c) 2010 Francois Lafortune, [email protected]
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