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Some fixes to elevator worksheet and once again trying to fix LaTeX t…
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…o PDF workflow.
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Staacks committed Jan 7, 2025
1 parent 4e2a993 commit 6a1130c
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1 change: 1 addition & 0 deletions .github/workflows/pandoc_texlive_packages.txt
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scheme-basic
amsfonts
amsmath
lm
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2 changes: 1 addition & 1 deletion content/de/instructions/aufzug/aufzug.md
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Expand Up @@ -64,7 +64,7 @@ Je nach Beadrf und Aufgabenstellung.

## Physikalischer Hintergrund und Analysedetails

Die Konfiguration „Aufzug“ nutzt die „internationale Höhenformel“ um den Luftdruck $p$ in eine Höhe $h$ umzurechnen.
Die Konfiguration „Aufzug“ nutzt die „internationale Höhenformel“ um den Luftdruck \(p\) in eine Höhe \(h\) umzurechnen.

$$
h = \frac{288,15\,\mathrm{K}}{0,0065\,\mathrm{\frac{K}{m}}}\left(1-\left(\frac{p(h)}{1013,25\,\mathrm{hPa}}\right)^{\frac{1}{5,255}}\right)
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5 changes: 2 additions & 3 deletions content/en/instructions/elevator/elevator.md
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categories:
- 'Mechanics'
sensors:
- 'Microphone'
- 'Accelerometer'
- 'Pressure'
levels: ['2a', '2b', '3', '6'] # see doc for explanation. Remove everything else
video: ['English']
materials:
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## Physics background and analysis details

The "Elevator" configuration uses the "international barometric formula" to convert air pressure $p$ into height $h$.
The "Elevator" configuration uses the "international barometric formula" to convert air pressure \(p\) into height \(h\).

$$
h = \frac{288.15\,\mathrm{K}}{0.0065\,\mathrm{\frac{K}{m}}}\left(1-\left(\frac{p(h)}{1013.25\,\mathrm{hPa}}\right)^{\frac{1}{5.255}}\right)
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