random(9,0) is always 9

[Symbol1]

Version: 3.1.7.a; I guess it's irrelevant.

On page 1042, or equivalently these two lines,
it is stated that if two numbers x, y are given, a random integer between x and y is generated.
However, if x > y, the generated number is always x.
Perhaps we can

• state in doc that x < y is expected, or
• modify the codebase to reorder x, y.

MWE

\documentclass{article}
\usepackage{tikz}
\begin{document}
	\foreach\ind in{1,...,99}{
		\pgfmathparse{random(0,9)}\pgfmathresult
	}
	\foreach\ind in{1,...,99}{
		\pgfmathparse{random(9,0)}\pgfmathresult
	}
\end{document}

[hmenke]

I think the order should not matter, so I reclassified this from manual to pgfmath bug.