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Signed-off-by: Marcello Seri <[email protected]>
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mseri committed Dec 7, 2021
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6 changes: 3 additions & 3 deletions 1-manifolds.tex
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Expand Up @@ -608,7 +608,7 @@ \section{Smooth maps and differentiability}\label{sec:smoothfn}

\begin{exercise}
Prove the proposition.\\
\textit{\small Hint: go cyclic, for example show $(i)\Rightarrow(ii)$, $(ii)\Rightarrow(iii)$, $(iii)\Rightarrow(i)$.}
\textit{\small Hint: go cyclic, for example show $(i)\Rightarrow(iii)$, $(iii)\Rightarrow(ii)$, $(ii)\Rightarrow(i)$.}
\end{exercise}

At this point, the generalization of smooth functions to smooth maps between manifolds should not come as a surprise.
Expand Down Expand Up @@ -1084,9 +1084,9 @@ \section{Manifolds with boundary}\label{sec:mbnd}
Let $M = D_1\subset \R^n$ be the $n$-dimensional closed unit ball from Example~\ref{ex:uball}.
\begin{enumerate}
\item Show that $M$ is a topological manifold with boundary in which each point of $\partial M = \bS^{n-1}$ is a boundary point and each point in $\mathring M = \{x\in\R^n\mid\|x\|<1\}$ is an interior point.
\item Give a smooth structure to $M$ such that every smooth interior chart is a smooth chart for the standard smooth structure on $\mathring M$.\\
\textit{\small Hint: consider the map $\pi\circ\sigma^{-1}:\R^n\to\R^n$ where $\sigma:\bS^n\to\R^n$ is the stereographic projection from Exercise~\ref{ex:stereo} and $\pi:\R^{n+1}\to\R^n$ is a projection that omits one of the first $n$ coordinates.}
\item Give a smooth structure to $M$ such that every smooth interior chart is a smooth chart for the standard smooth structure on $\mathring M$.
\end{enumerate}
\textit{\small Hint: consider the map $\pi\circ\sigma^{-1}:\R^n\to\R^n$ where $\sigma:\bS^n\to\R^n$ is the stereographic projection from Exercise~\ref{ex:stereo} and $\pi:\R^{n+1}\to\R^n$ is a projection that omits one of the first $n$ coordinates.}
\end{exercise}

\begin{tcolorbox}
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16 changes: 8 additions & 8 deletions 2-tangentbdl.tex
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Expand Up @@ -1119,7 +1119,7 @@ \section{Submanifolds}
\end{exercise}


In fact, also analogues of the implicit functions theorem carry over.
In fact, also analogues of the implicit function theorem carry over.
We will state them without going into the details of the proofs.

\begin{marginfigure}
Expand Down Expand Up @@ -1213,16 +1213,16 @@ \section{Submanifolds}
\begin{proposition}\label{prop:submanifolds_and_R}
The following assertions are equivalent.
\begin{enumerate}[(i)]
\item $P^k\subset N^n$ is a $k$-dimensional submanifold\footnote{So, $k \leq n$.}.
\item $P$ is locally the image of an embedding of a subset of $\R^k$.
That is, for every $p\in P$ there exists $V\subset P$ open neighbourhood of $p$, an open set $U\subset\R^k$ and an embedding
\item $P^n\subset M^m$ is a $n$-dimensional submanifold\footnote{So, $n \leq m$.}.
\item $P$ is locally the image of an embedding of a subset of $\R^n$.
That is, for every $p\in P$ there exists $g\subset P$ open neighbourhood of $p$, an open set $U\subset\R^n$ and an embedding
\begin{equation}
\varphi : U \to N \quad\mbox{such that}\quad \varphi(U)=V.
\varphi : U \to M \quad\mbox{such that}\quad \varphi(U)=V.
\end{equation}
\item $P$ is locally a level set of a submersion into $\R^{n-k}$.
That is, for every $p\in P$ there exists $V\subset P$ open neighbourhood of $p$ and a submersion $\psi: V \to\R^{n-k}$ such that
\item $P$ is locally a level set of a submersion into $\R^{m-n}$.
That is, for every $p\in P$ there exists $V\subset P$ open neighbourhood of $p$ and a submersion $\psi: V \to\R^{m-n}$ such that
\begin{equation}
N\cap V = \{q\in V \;\mid\; \psi(q) = 0\}.
M\cap V = \{q\in V \;\mid\; \psi(q) = 0\}.
\end{equation}
\end{enumerate}
\end{proposition}
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2 changes: 1 addition & 1 deletion aom.tex
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Expand Up @@ -213,7 +213,7 @@
\setlength{\parskip}{\baselineskip}
Copyright \copyright\ \the\year\ \thanklessauthor

\par Version 0.20 -- \today
\par Version 0.21 -- \today

\vfill
\small{\doclicenseThis}
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