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Introduce ParentReference adjuster (#3786)
* Introduce ParentReference adjuster As demonstrated in https://github.com/jaegertracing/jaeger-ui/issues/966, jaeger-ui expects the first reference to be of `CHILD_OF` type to properly render the tree. This new adjuster achieves exactly that. Signed-off-by: Ivan Babrou <[email protected]> * Simplify algorithm, clean-up tests Signed-off-by: Yuri Shkuro <[email protected]> Co-authored-by: Yuri Shkuro <[email protected]>
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// Copyright (c) 2022 The Jaeger Authors. | ||
// | ||
// Licensed under the Apache License, Version 2.0 (the "License"); | ||
// you may not use this file except in compliance with the License. | ||
// You may obtain a copy of the License at | ||
// | ||
// http://www.apache.org/licenses/LICENSE-2.0 | ||
// | ||
// Unless required by applicable law or agreed to in writing, software | ||
// distributed under the License is distributed on an "AS IS" BASIS, | ||
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. | ||
// See the License for the specific language governing permissions and | ||
// limitations under the License. | ||
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package adjuster | ||
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import ( | ||
"github.com/jaegertracing/jaeger/model" | ||
) | ||
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// ParentReference returns an Adjuster that puts CHILD_OF references first. | ||
// This is necessary to match jaeger-ui expectations: | ||
// * https://github.com/jaegertracing/jaeger-ui/issues/966 | ||
func ParentReference() Adjuster { | ||
return Func(func(trace *model.Trace) (*model.Trace, error) { | ||
for _, span := range trace.Spans { | ||
firstChildOfRef := -1 | ||
firstOtherRef := -1 | ||
for i := 1; i < len(span.References); i++ { | ||
if span.References[i].TraceID == span.TraceID { | ||
if span.References[i].RefType == model.SpanRefType_CHILD_OF { | ||
firstChildOfRef = i | ||
break | ||
} else if firstOtherRef == -1 { | ||
firstOtherRef = i | ||
} | ||
} | ||
} | ||
swap := firstChildOfRef | ||
if swap == -1 { | ||
swap = firstOtherRef | ||
} | ||
if swap != -1 { | ||
span.References[swap], span.References[0] = span.References[0], span.References[swap] | ||
} | ||
} | ||
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return trace, nil | ||
}) | ||
} |
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// Copyright (c) 2022 The Jaeger Authors. | ||
// | ||
// Licensed under the Apache License, Version 2.0 (the "License"); | ||
// you may not use this file except in compliance with the License. | ||
// You may obtain a copy of the License at | ||
// | ||
// http://www.apache.org/licenses/LICENSE-2.0 | ||
// | ||
// Unless required by applicable law or agreed to in writing, software | ||
// distributed under the License is distributed on an "AS IS" BASIS, | ||
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. | ||
// See the License for the specific language governing permissions and | ||
// limitations under the License. | ||
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package adjuster | ||
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import ( | ||
"testing" | ||
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"github.com/stretchr/testify/assert" | ||
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"github.com/jaegertracing/jaeger/model" | ||
) | ||
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func TestParentReference(t *testing.T) { | ||
a := model.NewTraceID(0, 1) | ||
b := model.NewTraceID(0, 2) | ||
childOf := func(id model.TraceID) model.SpanRef { | ||
return model.NewChildOfRef(id, 1) | ||
} | ||
followsFrom := func(id model.TraceID) model.SpanRef { | ||
return model.NewFollowsFromRef(id, 1) | ||
} | ||
followsFrom2 := func(id model.TraceID) model.SpanRef { | ||
return model.NewFollowsFromRef(id, 2) | ||
} | ||
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testCases := []struct { | ||
name string | ||
incoming []model.SpanRef | ||
expected []model.SpanRef | ||
}{ | ||
{ | ||
name: "empty", | ||
incoming: []model.SpanRef{}, | ||
expected: []model.SpanRef{}, | ||
}, | ||
{ | ||
name: "single child", | ||
incoming: []model.SpanRef{childOf(a)}, | ||
expected: []model.SpanRef{childOf(a)}, | ||
}, | ||
{ | ||
name: "single remote child", | ||
incoming: []model.SpanRef{childOf(b)}, | ||
expected: []model.SpanRef{childOf(b)}, | ||
}, | ||
{ | ||
name: "local and remote child in order", | ||
incoming: []model.SpanRef{childOf(a), childOf(b)}, | ||
expected: []model.SpanRef{childOf(a), childOf(b)}, | ||
}, | ||
{ | ||
name: "local and remote child out of order", | ||
incoming: []model.SpanRef{childOf(b), childOf(a)}, | ||
expected: []model.SpanRef{childOf(a), childOf(b)}, | ||
}, | ||
{ | ||
name: "local child, remote follows", | ||
incoming: []model.SpanRef{followsFrom(b), childOf(a)}, | ||
expected: []model.SpanRef{childOf(a), followsFrom(b)}, | ||
}, | ||
{ | ||
name: "remote, local, local follows - keep order", | ||
incoming: []model.SpanRef{followsFrom(b), followsFrom2(a), followsFrom(a)}, | ||
expected: []model.SpanRef{followsFrom2(a), followsFrom(b), followsFrom(a)}, | ||
}, | ||
{ | ||
name: "remote child, local follows", | ||
incoming: []model.SpanRef{childOf(b), followsFrom(a)}, | ||
expected: []model.SpanRef{followsFrom(a), childOf(b)}, | ||
}, | ||
{ | ||
name: "remote child, local follows, local child", | ||
incoming: []model.SpanRef{childOf(b), followsFrom(a), childOf(a)}, | ||
expected: []model.SpanRef{childOf(a), followsFrom(a), childOf(b)}, | ||
}, | ||
{ | ||
name: "remote follows, local follows, local child", | ||
incoming: []model.SpanRef{followsFrom(b), followsFrom(a), childOf(a)}, | ||
expected: []model.SpanRef{childOf(a), followsFrom(a), followsFrom(b)}, | ||
}, | ||
} | ||
for _, testCase := range testCases { | ||
t.Run(testCase.name, func(t *testing.T) { | ||
trace := &model.Trace{ | ||
Spans: []*model.Span{ | ||
{ | ||
TraceID: a, | ||
References: testCase.incoming, | ||
}, | ||
}, | ||
} | ||
trace, err := ParentReference().Adjust(trace) | ||
assert.NoError(t, err) | ||
assert.Equal(t, testCase.expected, trace.Spans[0].References) | ||
}) | ||
} | ||
} |