The memo
package implements a simple in-memory cache for the results of a function. If you have an expensive function that is being called repeatedly with the same inputs, memo
can help.
fib <- function(n) if (n <= 1) 1 else fib(n-1) + fib(n-2)
sapply(0:9, fib)
## [1] 1 1 2 3 5 8 13 21 34 55
This recursive implementation corresponds closely to the way the sequence is defined in math texts, but it has a performance problem. The problem is that as you ask for values further down the sequence, the computation becomes inordinately slow due to recursion. To demonstrate the issue, we can try counting every time fib
is
called:
count <- 0
fib <- function(n) {
count <<- count+1
if (n <= 1) 1 else fib(n-1) + fib(n-2)
}
counted_fib <- function(n) {
count <<- 0
c(n=n, result=fib(n), calls=count)
}
t(sapply(0:16, counted_fib))
## n result calls
## [1,] 0 1 1
## [2,] 1 1 1
## [3,] 2 2 3
## [4,] 3 3 5
## [5,] 4 5 9
## [6,] 5 8 15
## [7,] 6 13 25
## [8,] 7 21 41
## [9,] 8 34 67
## [10,] 9 55 109
## [11,] 10 89 177
## [12,] 11 144 287
## [13,] 12 233 465
## [14,] 13 377 753
## [15,] 14 610 1219
## [16,] 15 987 1973
## [17,] 16 1597 3193
The number of calls increases unreasonably. This is because, for instance, fib(6)
calls both fib(5)
and fib(4)
, but fib(5)
also calls fib(4)
. The second call to fib(4)
is wasted work. And this pattern goes on -- the two calls to fib(4)
lead to four calls to fib(2)
. Every time you increment n
by one, the number of calls roughly doubles. (Clearly, there are more efficient algorithms for computing the Fibbonacci sequence, but this is a toy example, where fib
stands in for some expensive function that is being called repeatedly.)
One way to cut down on wasted effort would be to check whether fib(n)
has already been computed for a given n
. If it has, fib
can just return that value instead of starting over. This is called "memoizing." The memo
package can automatically create a memoized version of a given function, just by wrapping the function definition in memo()
:
library(memo)
count <- 0
fib <- memo(function(n) {
count <<- count+1
if (n <= 1) 1 else fib(n-1) + fib(n-2)
})
counted_fib(16)
## n result calls
## 16 1597 17
Now, computing fib(16)
only takes 17 calls. And if we call again, it remembers the previous answer and doesn't make any new calls:
counted_fib(16)
## n result calls
## 16 1597 0
Each successive value then only takes two calls:
t(sapply(17:30, counted_fib))
## n result calls
## [1,] 17 2584 1
## [2,] 18 4181 2
## [3,] 19 6765 2
## [4,] 20 10946 2
## [5,] 21 17711 2
## [6,] 22 28657 2
## [7,] 23 46368 2
## [8,] 24 75025 2
## [9,] 25 121393 2
## [10,] 26 196418 2
## [11,] 27 317811 2
## [12,] 28 514229 2
## [13,] 29 832040 2
## [14,] 30 1346269 2
The tradeoff for this speedup is the memory used to store previous results. By default memo
will remember the 5000 most recently used results; to adjust that limit you can change the cache
option:
fib <- memo(cache=lru_cache(5000), function () {...})
The Fibonacci sequence being kind of a toy example, memoization has a variety of uses, such as:
- Caching the results of expensive database queries, for instance in Shiny apps where many users may make identical queries.
- Algorithms for path finding (dynamic programming) and parsing.
- Simulations such as Cellular automata.