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GH-38395: [Go] fix rounding errors in decimal256 string functions #38426
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Original file line number | Diff line number | Diff line change |
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@@ -266,23 +266,35 @@ func FromString(v string, prec, scale int32) (n Num, err error) { | |
return | ||
} | ||
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// Since we're going to truncate this to get an integer, we need to round | ||
// the value instead because of edge cases so that we match how other implementations | ||
// (e.g. C++) handles Decimal values. So if we're negative we'll subtract 0.5 and if | ||
// we're positive we'll add 0.5. | ||
out.Mul(out, big.NewFloat(math.Pow10(int(scale)))).SetPrec(precInBits) | ||
if out.Signbit() { | ||
out.Sub(out, pt5) | ||
if scale < 0 { | ||
var tmp big.Int | ||
val, _ := out.Int(&tmp) | ||
if val.BitLen() > 127 { | ||
return Num{}, errors.New("bitlen too large for decimal128") | ||
} | ||
n = FromBigInt(val) | ||
n, _ = n.Div(scaleMultipliers[-scale]) | ||
} else { | ||
out.Add(out, pt5) | ||
} | ||
// Since we're going to truncate this to get an integer, we need to round | ||
// the value instead because of edge cases so that we match how other implementations | ||
// (e.g. C++) handles Decimal values. So if we're negative we'll subtract 0.5 and if | ||
// we're positive we'll add 0.5. | ||
p := (&big.Float{}).SetInt(scaleMultipliers[scale].BigInt()) | ||
out.Mul(out, p).SetPrec(precInBits) | ||
if out.Signbit() { | ||
out.Sub(out, pt5) | ||
} else { | ||
out.Add(out, pt5) | ||
} | ||
Comment on lines
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. This is done because the round is a "round up", right? There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. more accurately it's a round away from zero There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. So -7.0 will become -7.0-0.5=-7.5 and round to -8.0? There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Not quite, check the comment above the spot: we truncate the value to get an integer. So -7.0 with a scale of 0 becomes -7.5 and then we truncate it to -7. -7.5 becomes -8.0 and then we truncate it to -8. A better example would be if we're given the value -0.75 with a scale of 1: The scale of 1 means that our final Decimal value is going to be the integer -8 because of rounding. There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Thank you for the explanation! |
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var tmp big.Int | ||
val, _ := out.Int(&tmp) | ||
if val.BitLen() > 127 { | ||
return Num{}, errors.New("bitlen too large for decimal128") | ||
var tmp big.Int | ||
val, _ := out.Int(&tmp) | ||
if val.BitLen() > 127 { | ||
return Num{}, errors.New("bitlen too large for decimal128") | ||
} | ||
n = FromBigInt(val) | ||
} | ||
n = FromBigInt(val) | ||
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if !n.FitsInPrecision(prec) { | ||
err = fmt.Errorf("val %v doesn't fit in precision %d", n, prec) | ||
} | ||
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@@ -505,7 +517,11 @@ func (n Num) FitsInPrecision(prec int32) bool { | |
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func (n Num) ToString(scale int32) string { | ||
f := (&big.Float{}).SetInt(n.BigInt()) | ||
f.Quo(f, (&big.Float{}).SetInt(scaleMultipliers[scale].BigInt())) | ||
if scale < 0 { | ||
f.SetPrec(128).Mul(f, (&big.Float{}).SetInt(scaleMultipliers[-scale].BigInt())) | ||
} else { | ||
f.SetPrec(128).Quo(f, (&big.Float{}).SetInt(scaleMultipliers[scale].BigInt())) | ||
} | ||
return f.Text('f', int(scale)) | ||
} | ||
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A-ha! I was reviewing commit by commit :)