-
Notifications
You must be signed in to change notification settings - Fork 8
Commit
This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository.
- Loading branch information
1 parent
a3faa4a
commit e58756d
Showing
1 changed file
with
70 additions
and
0 deletions.
There are no files selected for viewing
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,70 @@ | ||
/** | ||
450. Delete Node in a BST | ||
Solved | ||
Medium | ||
Topics | ||
Companies | ||
Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. | ||
Basically, the deletion can be divided into two stages: | ||
Search for a node to remove. | ||
If the node is found, delete the node. | ||
**/ | ||
/** | ||
* Definition for a binary tree node. | ||
* public class TreeNode { | ||
* int val; | ||
* TreeNode left; | ||
* TreeNode right; | ||
* TreeNode() {} | ||
* TreeNode(int val) { this.val = val; } | ||
* TreeNode(int val, TreeNode left, TreeNode right) { | ||
* this.val = val; | ||
* this.left = left; | ||
* this.right = right; | ||
* } | ||
* } | ||
*/ | ||
|
||
class Solution { | ||
public TreeNode deleteNode(TreeNode root, int key) { | ||
//search | ||
if(root == null ) { | ||
return null; | ||
} | ||
if(root.val<key){ | ||
root.right = deleteNode(root.right,key); | ||
} | ||
else if(root.val>key) { | ||
root.left = deleteNode(root.left,key); | ||
} | ||
else{ | ||
//case 1: leaf node | ||
if(root.left == null && root.right == null ) { | ||
return null; | ||
} | ||
//case 2 : one child | ||
if(root.left == null){ | ||
return root.right; | ||
} | ||
else if(root.right == null ) { | ||
return root.left; | ||
} | ||
//case 3 : two children | ||
TreeNode IS = findInOrderSuccessor(root.right); | ||
root.val = IS.val; | ||
|
||
|
||
root.right = deleteNode(root.right,IS.val); | ||
} | ||
return root; | ||
|
||
} | ||
private TreeNode findInOrderSuccessor(TreeNode root){ | ||
while(root.left != null){ | ||
root = root.left; | ||
} | ||
return root; | ||
} | ||
} |