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(Of course one could convert the IRI to a string and extract the label from it, but this becomes ugly if percent-encoding is involved.)
Is this maybe possible already? If not, would this be something that could be added to SPARQL Anything, or would this be in conflict with its design goals?
The text was updated successfully, but these errors were encountered:
this is something that applies to every format (the label can be generated once an xyz predicate is created).
An idea could be adding a new general option (e.g. generate-predicate-labels)
luigi-asprino
changed the title
rdfs:label for IRIs generated by docs.table-headers
Generate labels for the IRIs of classes and properties extracted from the source
Aug 6, 2024
Examples from https://sparql-anything.readthedocs.io/en/stable/formats/Word_Processing_Document/
docs.table-headers=false
:docs.table-headers=true
:When set to
true
, the generated RDF doesn’t contain "A", "B", and "C" as literals anymore.I think it would be useful if something like this would be generated:
(Of course one could convert the IRI to a string and extract the label from it, but this becomes ugly if percent-encoding is involved.)
Is this maybe possible already? If not, would this be something that could be added to SPARQL Anything, or would this be in conflict with its design goals?
The text was updated successfully, but these errors were encountered: