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Doubt about BeamDyn. #1435

Answered by jjonkman
aitorplaza asked this question in Q&A
Feb 5, 2023 · 1 comments · 1 reply
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Dear @aitorplaza,

It sounds like you are referring to BeamDyn's nodal outputs, in which case I agree that TVxg is the time-derivative of AbsXg. In BeamDyn, nodes are located at a given blade cross section, so the terms "node" and "section" in the BeamDyn documentation can be viewed as interchangeable.

Best regards,

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