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Create 498.cpp
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MainakRepositor authored Jun 5, 2021
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#include <iostream>

using namespace std;

// N is the size of the 2D matrix N*N
#define N 9

/* A utility function to print grid */
void print(int arr[N][N])
{
for (int i = 0; i < N; i++)
{
for (int j = 0; j < N; j++)
cout << arr[i][j] << " ";
cout << endl;
}
}

// Checks whether it will be
// legal to assign num to the
// given row, col
bool isSafe(int grid[N][N], int row,
int col, int num)
{

// Check if we find the same num
// in the similar row , we
// return false
for (int x = 0; x <= 8; x++)
if (grid[row][x] == num)
return false;

// Check if we find the same num in
// the similar column , we
// return false
for (int x = 0; x <= 8; x++)
if (grid[x][col] == num)
return false;

// Check if we find the same num in
// the particular 3*3 matrix,
// we return false
int startRow = row - row % 3,
startCol = col - col % 3;

for (int i = 0; i < 3; i++)
for (int j = 0; j < 3; j++)
if (grid[i + startRow][j +
startCol] == num)
return false;

return true;
}

/* Takes a partially filled-in grid and attempts
to assign values to all unassigned locations in
such a way to meet the requirements for
Sudoku solution (non-duplication across rows,
columns, and boxes) */
bool solveSuduko(int grid[N][N], int row, int col)
{
// Check if we have reached the 8th
// row and 9th column (0
// indexed matrix) , we are
// returning true to avoid
// further backtracking
if (row == N - 1 && col == N)
return true;

// Check if column value becomes 9 ,
// we move to next row and
// column start from 0
if (col == N) {
row++;
col = 0;
}

// Check if the current position of
// the grid already contains
// value >0, we iterate for next column
if (grid[row][col] > 0)
return solveSuduko(grid, row, col + 1);

for (int num = 1; num <= N; num++)
{

// Check if it is safe to place
// the num (1-9) in the
// given row ,col ->we
// move to next column
if (isSafe(grid, row, col, num))
{

/* Assigning the num in
the current (row,col)
position of the grid
and assuming our assined
num in the position
is correct */
grid[row][col] = num;

// Checking for next possibility with next
// column
if (solveSuduko(grid, row, col + 1))
return true;
}

// Removing the assigned num ,
// since our assumption
// was wrong , and we go for
// next assumption with
// diff num value
grid[row][col] = 0;
}
return false;
}

// Driver Code
int main()
{
// 0 means unassigned cells
int grid[N][N] = { { 3, 0, 6, 5, 0, 8, 4, 0, 0 },
{ 5, 2, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 8, 7, 0, 0, 0, 0, 3, 1 },
{ 0, 0, 3, 0, 1, 0, 0, 8, 0 },
{ 9, 0, 0, 8, 6, 3, 0, 0, 5 },
{ 0, 5, 0, 0, 9, 0, 6, 0, 0 },
{ 1, 3, 0, 0, 0, 0, 2, 5, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 7, 4 },
{ 0, 0, 5, 2, 0, 6, 3, 0, 0 } };

if (solveSuduko(grid, 0, 0))
print(grid);
else
cout << "no solution exists " << endl;

return 0;

}

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