THIS PROJECT IS NO LONGER MAINTAINED.
WILL COME UP WITH NEW ONE INCLUDING MORE USECASES, FLEXIBLE ARCHITECTURE & ONE FOR SWIFTUI TOO
Expand cells in TableView up to ∞-1. You can use any Custom Cell for any Parent, Childs or their Subchilds
- Static Initialization
- Static Initialization using Index
- Dynamic Initialization using JSON
- Custom Cell
- Control of Cells
- Fast scrolling, memory efficient
- Well unit tested
KJExpandableTableTree is available through CocoaPods. To install it, simply add the following line to your Podfile:
pod 'KJExpandableTableTree'There are 3 ways to initialize this library.
You can choose any either way to create tree. Static/Dynamic.
Example folder.
I've used Tree.json file for JSON Array.
{
"Tree": {
"Id": 0,
"Parents": [
{
"Id": 1,
"Children": [
{
"Id": 2,
"Children": null
},
{
"Id": 3,
"Children": [
{
"Id": 28,
"Children": [
{
"Id": 29,
"Children": null
}
]
}
]
}
]
},
{
"Id": 4,
"Children": null
}
]
}
}Initialize KJTree with JSON array of Parents similar to below, Provide required Key's name and YOUR ARE DONE.
// KJ Tree instances -------------------------
var kjtreeInstance: KJTree? = nil
var arrayParents: NSArray?
if let treeDictionary = jsonDictionary?.object(forKey: "Tree") as? NSDictionary {
if let arrayOfParents = treeDictionary.object(forKey: "Parents") as? NSArray {
arrayParents = arrayOfParents
}
}
if let arrayOfParents = arrayParents {
kjtreeInstance = KJTree(parents: arrayOfParents, childrenKey: "Children", idKey: "Id")
}
Example folder.
// KJ Tree instances -------------------------
// You can easily create tree by Indexing.
// below, There will be 3 parents -
// 1.1 indicates 1 child inside 1st parent.
// in Second, 2nd parent have 1 child (2.1....), That 1 child have 3 subchilds (2.1.1..., 2.1.2..., 2.1.3...), now it's easy to understand 2.1.3.2 and 2.1.3.3 means 2 sub childs inside 2.1.3.
// in Third, 3rd parent have 3 childs. 1, 2, 3.
kjtreeInstance = KJTree(indices:
["1.1",
"2.1.1",
"2.1.2.1",
"2.1.3.2",
"2.1.3.3",
"3.1",
"3.2",
"3.3"]
)
Example folder.
Swifty robust way to initialize this library
// KJ Tree instances -------------------------
var kjtreeInstance: KJTree?
// You can easily identify here, I've one parent called parent1, 3 childs inside it, 2 sub childs inside 2nd child, and 2 more sub childs inside 2nd sub child.
// You can add as many as internal level of childs hierarchy.
// I've provided a block of each parent and child, use this block to return no of childs [Child] inside parent/child.
// this will provide you a robust visibility of static tree.
let parent1 = Parent() { () -> [Child] in
let child1 = Child()
let child2 = Child(subChilds: { () -> [Child] in
let subchild1 = Child()
let subchild2 = Child(subChilds: { () -> [Child] in
let subchild1 = Child()
let subchild2 = Child(subChilds: { () -> [Child] in
let subchild1 = Child()
return [subchild1]
})
return [subchild1, subchild2]
})
return [subchild1, subchild2]
})
let child3 = Child()
return [child1, child2, child3]
}
kjtreeInstance? = KJTree(Parents: [parent1])I've added 2 more parents for my demo simulation
Use UITableView delegates, as you guys are using, simply call library Methods from your delegates.
Call tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> NSInteger to return number of cells.
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return kjtreeInstance.tableView(tableView, numberOfRowsInSection: section)
}Call cellIdentifierUsingTableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> Node to receive Node instance.
Use node.index to get index of each cell to be shown in tableview.
For parents you will receive 0,1,2,... for childs 0.0, 0.1, 0.2, 1.0, 1.1,.... for sub childs 0.0.0, 0.0.1, 0.1.0, 1.0.0, 1.1.1, .... and so one for sub childs of sub childs you will receive 4 index separated by . (dot)
NOTE: You can return custom cells based on your needs, I've enclosed 3 examples to show you guys how you can return cells for different purpose.
Example_Static_Init - Return cell by Levels.
Example_Static_Init_Using_Index - Return cell by your assigned Custom Index
Example_Dynamic_Init - cell by Levels. You can use your given identity at node.givenIndex or actual index provided by me to return different cell based on your needs.
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let node = kjtreeInstance.cellIdentifierUsingTableView(tableView, cellForRowAt: indexPath)
// You can return different cells for Parents, childs, subchilds, .... as below.
let indexTuples = node.index.components(separatedBy: ".")
if indexTuples.count == 1 || indexTuples.count == 4 {
// return cell for Parents and subchilds at level 4. (For Level-1 and Internal level-4)
}else if indexTuples.count == 2{
// return cell for Childs of Parents. (Level-2)
}else if indexTuples.count == 3{
// return cell for Subchilds of Childs inside Parent. (Level-3)
}
// Return below cell for more internal levels....
var tableviewcell = tableView.dequeueReusableCell(withIdentifier: "cellidentity")
if tableviewcell == nil {
tableviewcell = UITableViewCell(style: .default, reuseIdentifier: "cellidentity")
}
tableviewcell?.textLabel?.text = node.index
tableviewcell?.backgroundColor = UIColor.yellow
tableviewcell?.selectionStyle = .none
return tableviewcell!
}Call tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) -> KJExpandableTableTree.Node to receive Node instance.
Use node instance and it's index/givenIndex to verify specific cell press, to do additional task in your tableview's didSelectRowAt.
func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
let node = kjtreeInstance.tableView(tableView, didSelectRowAt: indexPath)
print(node.index)
// if you've provided a 'Key'/'Id', you will receive it here.
print(node.keyIdentity)
// if you've added any identifier or used indexing format
print(node.givenIndex)
}Kiran Jasvanee, [email protected]
KJExpandableTableTree is available under the MIT license. See the LICENSE file for more info.