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inference: fix typeof-tfunc impl (#31405)
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vtjnash authored Mar 21, 2019
1 parent 54fe55b commit 604c9b2
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Showing 2 changed files with 5 additions and 1 deletion.
2 changes: 1 addition & 1 deletion base/compiler/tfuncs.jl
Original file line number Diff line number Diff line change
Expand Up @@ -450,7 +450,7 @@ function typeof_tfunc(@nospecialize(t))
a = widenconst(typeof_tfunc(t.a))
b = widenconst(typeof_tfunc(t.b))
return Union{a, b}
elseif isa(t, TypeVar) && !(Any <: t.ub)
elseif isa(t, TypeVar) && !(Any === t.ub)
return typeof_tfunc(t.ub)
elseif isa(t, UnionAll)
u = unwrap_unionall(t)
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4 changes: 4 additions & 0 deletions test/compiler/inference.jl
Original file line number Diff line number Diff line change
Expand Up @@ -1353,6 +1353,10 @@ using Core.Compiler: typeof_tfunc
@test typeof_tfunc(Type{<:Array}) === DataType
@test typeof_tfunc(Array{Int}) == Type{Array{Int,N}} where N
@test typeof_tfunc(AbstractArray{Int}) == Type{<:AbstractArray{Int,N}} where N
@test typeof_tfunc(Union{<:T, <:Real} where T<:Complex) == Union{Type{Complex{T}} where T<:Real, Type{<:Real}}

f_typeof_tfunc(x) = typeof(x)
@test Base.return_types(f_typeof_tfunc, (Union{<:T, Int} where T<:Complex,)) == Any[Union{Type{Int}, Type{Complex{T}} where T<:Real}]

function f23024(::Type{T}, ::Int) where T
1 + 1
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