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Make Uint256::from_{le,be}_bytes and ::new const #1071
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Simple solution. Makes sense to me 👍
pub const fn from_be_bytes(data: [u8; 32]) -> Self { | ||
let words: [u64; 4] = [ | ||
u64::from_le_bytes([ | ||
data[31], data[30], data[29], data[28], data[27], data[26], data[25], data[24], | ||
]), | ||
u64::from_le_bytes([ | ||
data[23], data[22], data[21], data[20], data[19], data[18], data[17], data[16], | ||
]), | ||
u64::from_le_bytes([ | ||
data[15], data[14], data[13], data[12], data[11], data[10], data[9], data[8], | ||
]), | ||
u64::from_le_bytes([ | ||
data[7], data[6], data[5], data[4], data[3], data[2], data[1], data[0], | ||
]), | ||
]; | ||
Uint256(U256(words)) | ||
} |
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I feel embarrassed I didn't think of the simple solution here. I tried to slice the data
and failed because I couldn't transform/convert it in a const
context.
Nice!
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | ||
0, 0, 42, | ||
]); | ||
assert_eq!(a, Uint256::from(42u128)); |
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Douglas Adams is the best.
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This is a PoC. Testing is incomplete and we also want a version for big endian in order to makenew
const.Based on #1073