Qm_method

solution(minterm:list) #메인함수

minterm #데이터가 담긴 list

minterm의 구성

[variable size, minterm1, minterm2, minterm3, ….]

테스트 케이스

minterm = [4, 1, 2, 3, 4, 6, 7, 8, 9, 11, 12, 13, 15]

minterm = [4, 0, 4, 12, 8, 13, 15, 11, 10]

minterm = [5, 1, 2, 3, 5, 6, 7, 8, 9, 10, 11, 12, 14, 17, 20, 21, 23, 24, 26, 27]

minterm = [5, 1, 2, 3, 4, 5, 6, 7, 20, 21, 23, 24, 26, 27 ,28, 29, 30]

minterm = [3, 0, 1, 2, 5, 6, 7] #no epi

minterm = [3, 0, 1, 2, 5, 6, 7]

minterm = [4, 1, 2, 3, 5, 7, 8, 10, 13, 15]

minterm = [4, 0, 1, 2 ,4, 5, 6, 9, 10, 11, 13, 14, 15]

minterm = [3, 1, 3, 4, 6, 7]

minterm = [6, 1, 2, 3, 5, 7, 8, 9, 10, 11, 12 ,13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 25, 26, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63]