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Laneia #30
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Laneia #30
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Original file line number | Diff line number | Diff line change |
---|---|---|
|
@@ -2,61 +2,137 @@ class TreeNode | |
attr_reader :key, :value | ||
attr_accessor :left, :right | ||
|
||
def initialize(key, val) | ||
def initialize(key, val) | ||
@key = key | ||
@value = val | ||
@left = nil | ||
@right = nil | ||
end | ||
end | ||
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||
def add(key, value) | ||
if key == @key | ||
return | ||
elsif key < @key | ||
left.nil? ? @left = TreeNode.new(key, value) : left.add(key, value) | ||
elsif key > @key | ||
right.nil? ? @right = TreeNode.new(key, value) : right.add(key, value) | ||
end | ||
end | ||
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||
def find(key) | ||
if key == @key | ||
return @value | ||
elsif key < @key | ||
left.nil? ? nil : left.find(key) | ||
elsif key > @key | ||
right.nil? ? nil : right.find(key) | ||
end | ||
end | ||
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||
def inorder(array) | ||
left.inorder(array) unless left.nil? | ||
array << {key: @key, value: @value} | ||
right.inorder(array) unless right.nil? | ||
end | ||
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||
def preorder(array) | ||
array << {key: @key, value: @value} | ||
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||
if left | ||
left.preorder(array) | ||
end | ||
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||
if right | ||
right.preorder(array) | ||
end | ||
end | ||
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||
def postorder(array) | ||
if left | ||
left.postorder(array) | ||
end | ||
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||
if right | ||
right.postorder(array) | ||
end | ||
array << {key: @key, value: @value} | ||
end | ||
end | ||
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||
class Tree | ||
attr_reader :root | ||
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def initialize | ||
@root = nil | ||
end | ||
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# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: O(log n) if balanced tree, O(n) if unbalanced, n = # nodes in tree | ||
# Space Complexity: O(log n) if balanced tree, O(n) if unbalanced, n = # nodes in tree | ||
def add(key, value) | ||
raise NotImplementedError | ||
if root.nil? | ||
@root = TreeNode.new(key, value) | ||
else | ||
root.add(key, value) | ||
end | ||
end | ||
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||
# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: O(log n) if balanced tree, O(n) if unbalanced, n = # nodes in tree | ||
# Space Complexity: O(log n) if balanced tree, O(n) if unbalanced, n = # nodes in tree | ||
def find(key) | ||
raise NotImplementedError | ||
if root.nil? | ||
return nil | ||
else | ||
root.find(key) | ||
end | ||
end | ||
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||
# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: O(n),n = # nodes in tree | ||
# Space Complexity: O(n), n = # nodes in tree | ||
def inorder | ||
raise NotImplementedError | ||
array = [] | ||
if root.nil? | ||
return array | ||
else | ||
root.inorder(array) | ||
return array | ||
end | ||
end | ||
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||
# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: O(n), n = # nodes in tree | ||
# Space Complexity: O(n), n = # nodes in tree | ||
def preorder | ||
raise NotImplementedError | ||
array = [] | ||
if root.nil? | ||
return array | ||
else | ||
root.preorder(array) | ||
return array | ||
end | ||
end | ||
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||
# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: O(n), n = # nodes in tree | ||
# Space Complexity: O(n), n = # nodes in tree | ||
def postorder | ||
raise NotImplementedError | ||
array = [] | ||
if root.nil? | ||
return array | ||
else | ||
root.postorder(array) | ||
return array | ||
end | ||
end | ||
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||
# Time Complexity: | ||
# Space Complexity: | ||
def height | ||
raise NotImplementedError | ||
end | ||
# Time Complexity: O(n), n = # nodes in tree | ||
# Space Complexity: O(1) | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Since this is recursive, you have the system stack being used here and the space complexity is O(Log n) |
||
def height(current = @root) | ||
if current | ||
lh = height(current.left) | ||
rh = height(current.right) | ||
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# Optional Method | ||
# Time Complexity: | ||
# Space Complexity: | ||
def bfs | ||
raise NotImplementedError | ||
(lh > rh ? lh : rh) + 1 | ||
else | ||
0 | ||
end | ||
end | ||
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||
# Useful for printing | ||
|
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Yes since you're doing recursion