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Jansen #7

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32 changes: 26 additions & 6 deletions lib/heap_sort.rb
Original file line number Diff line number Diff line change
@@ -1,8 +1,28 @@

require_relative "min_heap"

# This method uses a heap to sort an array.
# Time Complexity: ?
# Space Complexity: ?
def heap_sort(list)
raise NotImplementedError, "Method not implemented yet..."
end
# Time Complexity: O(n log n)
# Space Complexity: O(n) times the number of recursive operations required to finish sorting
def heapsort(list)
return list if list == [] || list.length == 1

# initialize new heap
heap = MinHeap.new

# add each element in list to heap's store
list.each do |num|
key = num
value = num

heap.add(key, value)
end

sorted_list = []
# take each element out of heap's store, keep it in another array
list.length.times do
removed = heap.remove
sorted_list << removed
end

return sorted_list
end
83 changes: 65 additions & 18 deletions lib/min_heap.rb
Original file line number Diff line number Diff line change
Expand Up @@ -8,26 +8,38 @@ def initialize(key, value)
end

class MinHeap

def initialize
@store = []
end

# This method adds a HeapNode instance to the heap
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(log n), where n is the number of nodes in the heap
# Space complexity: O(log n), where n is the number of nodes in the heap. The reason it's O(log n) (and not O(1)) is
# because we're calling this method recursively.
def add(key, value = key)
raise NotImplementedError, "Method not implemented yet..."
new_node = HeapNode.new(key, value)
@store << new_node

heap_up(@store.length - 1)
end

# This method removes and returns an element from the heap
# maintaining the heap structure
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(log n), where n is the number of nodes in the heap
# Space complexity: O(log n), where n is the number of nodes in the heap. The reason it's O(log n) (and not O(1)) is
# because we're calling this method recursively.
def remove()
raise NotImplementedError, "Method not implemented yet..."
end
root = @store[0]
new_root = @store[@store.length - 1]

@store[@store.length - 1] = root
@store[0] = new_root

removed = @store.pop

heap_down(0)
return removed.value
end

# Used for Testing
def to_s
Expand All @@ -39,33 +51,68 @@ def to_s
end

output += @store.last.value + "]"

return output
end

# This method returns true if the heap is empty
# Time complexity: ?
# Space complexity: ?
# Time complexity: O(1), because we're making a straight comparison
# Space complexity: O(1), because there are no extra variables that change with input size
def empty?
raise NotImplementedError, "Method not implemented yet..."
return true if @store == []
return false
end

private

# This helper method takes an index and
# moves it up the heap, if it is less than it's parent node.
# It could be **very** helpful for the add method.
# Time complexity: ?
# Space complexity: ?
# Time complexity: O(log n), where n is the number of nodes in the heap
# Space complexity: O(log n), where n is the number of nodes in the heap. The reason it's O(log n) (and not O(1)) is
# because we're calling this method recursively.
def heap_up(index)

# get parent index based on child's position
parent_index = (index - 1) / 2

# return the array if there's no parent, or parent is less than or equal to child
return @store if parent_index < 0 || @store[index].key >= @store[parent_index].key

swap(parent_index, index)

# call recursively on child's new position
heap_up(parent_index)
end

# This helper method takes an index and
# This helper method takes an index and
# moves it up the heap if it's smaller
# than it's parent node.
def heap_down(index)
raise NotImplementedError, "Method not implemented yet..."
left_child = 2 * index + 1
right_child = 2 * index + 2
min_child = nil

# Return if there's no left child
return if left_child > @store.length - 1

# If there's no RIGHT child AND parent is greater than LEFT child...
# swap parent with left child
if @store[right_child].nil? && @store[index].key > @store[left_child].key
swap(index, left_child)
heap_down(index)
elsif @store[right_child] #Otherwise, which child is min?
if @store[right_child].key <= @store[left_child].key
min_child = @store.index(@store[right_child])
else
min_child = @store.index(@store[left_child])
end
end

# If parent is greater than minimum child, swap them
if min_child && @store[index].key > @store[min_child].key
swap(index, min_child)
heap_down(index)
end
end

# If you want a swap method... you're welcome
Expand All @@ -74,4 +121,4 @@ def swap(index_1, index_2)
@store[index_1] = @store[index_2]
@store[index_2] = temp
end
end
end
14 changes: 7 additions & 7 deletions test/heapsort_test.rb
Original file line number Diff line number Diff line change
@@ -1,8 +1,8 @@
require_relative "test_helper"

xdescribe "heapsort" do
describe "heapsort" do
it "sorts an empty array" do
# Arrange
# Arrange
list = []

# Act
Expand All @@ -13,7 +13,7 @@
end

it "can sort a 1-element array" do
# Arrange
# Arrange
list = [5]

# Act
Expand All @@ -22,15 +22,15 @@
# Assert
expect(result).must_equal [5]
end

it "can sort a 5-element array" do
# Arrange
# Arrange
list = [5, 27, 3, 16, -50]

# Act
result = heapsort(list)

# Assert
expect(result).must_equal [-50, 3, 5, 16, 27]
end
end
end
end