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z
[1..2^128)
It doesn't really matter whether we use the full field or not (as long as z != 0), but it makes various scalar mults cheaper.
z != 0
Originally posted by @str4d in #59 (comment)
The text was updated successfully, but these errors were encountered:
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It doesn't really matter whether we use the full field or not (as long as
z != 0
), but it makes various scalar mults cheaper.Originally posted by @str4d in #59 (comment)
The text was updated successfully, but these errors were encountered: