comments | difficulty | edit_url | tags | |
---|---|---|---|---|
true |
Medium |
|
Table: Tasks
+-------------+------+ | Column Name | Type | +-------------+------+ | task_id | int | | assignee_id | int | | submit_date | date | +-------------+------+ task_id is the primary key (column with unique values) for this table. Each row in this table contains the ID of a task, the id of the assignee, and the submission date.
Write a solution to report:
- the number of tasks that were submitted during the weekend (Saturday, Sunday) as
weekend_cnt
, and - the number of tasks that were submitted during the working days as
working_cnt
.
Return the result table in any order.
The result format is shown in the following example.
Example 1:
Input: Tasks table: +---------+-------------+-------------+ | task_id | assignee_id | submit_date | +---------+-------------+-------------+ | 1 | 1 | 2022-06-13 | | 2 | 6 | 2022-06-14 | | 3 | 6 | 2022-06-15 | | 4 | 3 | 2022-06-18 | | 5 | 5 | 2022-06-19 | | 6 | 7 | 2022-06-19 | +---------+-------------+-------------+ Output: +-------------+-------------+ | weekend_cnt | working_cnt | +-------------+-------------+ | 3 | 3 | +-------------+-------------+ Explanation: Task 1 was submitted on Monday. Task 2 was submitted on Tuesday. Task 3 was submitted on Wednesday. Task 4 was submitted on Saturday. Task 5 was submitted on Sunday. Task 6 was submitted on Sunday. 3 tasks were submitted during the weekend. 3 tasks were submitted during the working days.
# Write your MySQL query statement below
SELECT
SUM(WEEKDAY(submit_date) IN (5, 6)) AS weekend_cnt,
SUM(WEEKDAY(submit_date) NOT IN (5, 6)) AS working_cnt
FROM Tasks;