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Medium
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Weekly Contest 256 Q2
Array
String
Divide and Conquer
Quickselect
Sorting
Heap (Priority Queue)

中文文档

Description

You are given an array of strings nums and an integer k. Each string in nums represents an integer without leading zeros.

Return the string that represents the kth largest integer in nums.

Note: Duplicate numbers should be counted distinctly. For example, if nums is ["1","2","2"], "2" is the first largest integer, "2" is the second-largest integer, and "1" is the third-largest integer.

 

Example 1:

Input: nums = ["3","6","7","10"], k = 4
Output: "3"
Explanation:
The numbers in nums sorted in non-decreasing order are ["3","6","7","10"].
The 4th largest integer in nums is "3".

Example 2:

Input: nums = ["2","21","12","1"], k = 3
Output: "2"
Explanation:
The numbers in nums sorted in non-decreasing order are ["1","2","12","21"].
The 3rd largest integer in nums is "2".

Example 3:

Input: nums = ["0","0"], k = 2
Output: "0"
Explanation:
The numbers in nums sorted in non-decreasing order are ["0","0"].
The 2nd largest integer in nums is "0".

 

Constraints:

  • 1 <= k <= nums.length <= 104
  • 1 <= nums[i].length <= 100
  • nums[i] consists of only digits.
  • nums[i] will not have any leading zeros.

Solutions

Solution 1

Python3

class Solution:
    def kthLargestNumber(self, nums: List[str], k: int) -> str:
        def cmp(a, b):
            if len(a) != len(b):
                return len(b) - len(a)
            return 1 if b > a else -1

        nums.sort(key=cmp_to_key(cmp))
        return nums[k - 1]

Java

class Solution {
    public String kthLargestNumber(String[] nums, int k) {
        Arrays.sort(
            nums, (a, b) -> a.length() == b.length() ? b.compareTo(a) : b.length() - a.length());
        return nums[k - 1];
    }
}

C++

class Solution {
public:
    string kthLargestNumber(vector<string>& nums, int k) {
        auto cmp = [](const string& a, const string& b) { return a.size() == b.size() ? a > b : a.size() > b.size(); };
        sort(nums.begin(), nums.end(), cmp);
        return nums[k - 1];
    }
};

Go

func kthLargestNumber(nums []string, k int) string {
	sort.Slice(nums, func(i, j int) bool {
		a, b := nums[i], nums[j]
		if len(a) == len(b) {
			return a > b
		}
		return len(a) > len(b)
	})
	return nums[k-1]
}