comments | difficulty | edit_url | tags | ||||
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true |
Medium |
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Design a time-based key-value data structure that can store multiple values for the same key at different time stamps and retrieve the key's value at a certain timestamp.
Implement the TimeMap
class:
TimeMap()
Initializes the object of the data structure.void set(String key, String value, int timestamp)
Stores the keykey
with the valuevalue
at the given timetimestamp
.String get(String key, int timestamp)
Returns a value such thatset
was called previously, withtimestamp_prev <= timestamp
. If there are multiple such values, it returns the value associated with the largesttimestamp_prev
. If there are no values, it returns""
.
Example 1:
Input ["TimeMap", "set", "get", "get", "set", "get", "get"] [[], ["foo", "bar", 1], ["foo", 1], ["foo", 3], ["foo", "bar2", 4], ["foo", 4], ["foo", 5]] Output [null, null, "bar", "bar", null, "bar2", "bar2"] Explanation TimeMap timeMap = new TimeMap(); timeMap.set("foo", "bar", 1); // store the key "foo" and value "bar" along with timestamp = 1. timeMap.get("foo", 1); // return "bar" timeMap.get("foo", 3); // return "bar", since there is no value corresponding to foo at timestamp 3 and timestamp 2, then the only value is at timestamp 1 is "bar". timeMap.set("foo", "bar2", 4); // store the key "foo" and value "bar2" along with timestamp = 4. timeMap.get("foo", 4); // return "bar2" timeMap.get("foo", 5); // return "bar2"
Constraints:
1 <= key.length, value.length <= 100
key
andvalue
consist of lowercase English letters and digits.1 <= timestamp <= 107
- All the timestamps
timestamp
ofset
are strictly increasing. - At most
2 * 105
calls will be made toset
andget
.
class TimeMap:
def __init__(self):
self.ktv = defaultdict(list)
def set(self, key: str, value: str, timestamp: int) -> None:
self.ktv[key].append((timestamp, value))
def get(self, key: str, timestamp: int) -> str:
if key not in self.ktv:
return ''
tv = self.ktv[key]
i = bisect_right(tv, (timestamp, chr(127)))
return tv[i - 1][1] if i else ''
# Your TimeMap object will be instantiated and called as such:
# obj = TimeMap()
# obj.set(key,value,timestamp)
# param_2 = obj.get(key,timestamp)
class TimeMap {
private Map<String, TreeMap<Integer, String>> ktv = new HashMap<>();
public TimeMap() {
}
public void set(String key, String value, int timestamp) {
ktv.computeIfAbsent(key, k -> new TreeMap<>()).put(timestamp, value);
}
public String get(String key, int timestamp) {
if (!ktv.containsKey(key)) {
return "";
}
var tv = ktv.get(key);
Integer t = tv.floorKey(timestamp);
return t == null ? "" : tv.get(t);
}
}
/**
* Your TimeMap object will be instantiated and called as such:
* TimeMap obj = new TimeMap();
* obj.set(key,value,timestamp);
* String param_2 = obj.get(key,timestamp);
*/
class TimeMap {
public:
TimeMap() {
}
void set(string key, string value, int timestamp) {
ktv[key].emplace_back(timestamp, value);
}
string get(string key, int timestamp) {
auto& pairs = ktv[key];
pair<int, string> p = {timestamp, string({127})};
auto i = upper_bound(pairs.begin(), pairs.end(), p);
return i == pairs.begin() ? "" : (i - 1)->second;
}
private:
unordered_map<string, vector<pair<int, string>>> ktv;
};
/**
* Your TimeMap object will be instantiated and called as such:
* TimeMap* obj = new TimeMap();
* obj->set(key,value,timestamp);
* string param_2 = obj->get(key,timestamp);
*/
type TimeMap struct {
ktv map[string][]pair
}
func Constructor() TimeMap {
return TimeMap{map[string][]pair{}}
}
func (this *TimeMap) Set(key string, value string, timestamp int) {
this.ktv[key] = append(this.ktv[key], pair{timestamp, value})
}
func (this *TimeMap) Get(key string, timestamp int) string {
pairs := this.ktv[key]
i := sort.Search(len(pairs), func(i int) bool { return pairs[i].t > timestamp })
if i > 0 {
return pairs[i-1].v
}
return ""
}
type pair struct {
t int
v string
}
/**
* Your TimeMap object will be instantiated and called as such:
* obj := Constructor();
* obj.Set(key,value,timestamp);
* param_2 := obj.Get(key,timestamp);
*/