comments | difficulty | edit_url | tags | ||||
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true |
Medium |
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Design a data structure that supports adding new words and finding if a string matches any previously added string.
Implement the WordDictionary
class:
WordDictionary()
Initializes the object.void addWord(word)
Addsword
to the data structure, it can be matched later.bool search(word)
Returnstrue
if there is any string in the data structure that matchesword
orfalse
otherwise.word
may contain dots'.'
where dots can be matched with any letter.
Example:
Input ["WordDictionary","addWord","addWord","addWord","search","search","search","search"] [[],["bad"],["dad"],["mad"],["pad"],["bad"],[".ad"],["b.."]] Output [null,null,null,null,false,true,true,true] Explanation WordDictionary wordDictionary = new WordDictionary(); wordDictionary.addWord("bad"); wordDictionary.addWord("dad"); wordDictionary.addWord("mad"); wordDictionary.search("pad"); // return False wordDictionary.search("bad"); // return True wordDictionary.search(".ad"); // return True wordDictionary.search("b.."); // return True
Constraints:
1 <= word.length <= 25
word
inaddWord
consists of lowercase English letters.word
insearch
consist of'.'
or lowercase English letters.- There will be at most
2
dots inword
forsearch
queries. - At most
104
calls will be made toaddWord
andsearch
.
class Trie:
def __init__(self):
self.children = [None] * 26
self.is_end = False
class WordDictionary:
def __init__(self):
self.trie = Trie()
def addWord(self, word: str) -> None:
node = self.trie
for c in word:
idx = ord(c) - ord('a')
if node.children[idx] is None:
node.children[idx] = Trie()
node = node.children[idx]
node.is_end = True
def search(self, word: str) -> bool:
def search(word, node):
for i in range(len(word)):
c = word[i]
idx = ord(c) - ord('a')
if c != '.' and node.children[idx] is None:
return False
if c == '.':
for child in node.children:
if child is not None and search(word[i + 1 :], child):
return True
return False
node = node.children[idx]
return node.is_end
return search(word, self.trie)
# Your WordDictionary object will be instantiated and called as such:
# obj = WordDictionary()
# obj.addWord(word)
# param_2 = obj.search(word)
class Trie {
Trie[] children = new Trie[26];
boolean isEnd;
}
class WordDictionary {
private Trie trie;
/** Initialize your data structure here. */
public WordDictionary() {
trie = new Trie();
}
public void addWord(String word) {
Trie node = trie;
for (char c : word.toCharArray()) {
int idx = c - 'a';
if (node.children[idx] == null) {
node.children[idx] = new Trie();
}
node = node.children[idx];
}
node.isEnd = true;
}
public boolean search(String word) {
return search(word, trie);
}
private boolean search(String word, Trie node) {
for (int i = 0; i < word.length(); ++i) {
char c = word.charAt(i);
int idx = c - 'a';
if (c != '.' && node.children[idx] == null) {
return false;
}
if (c == '.') {
for (Trie child : node.children) {
if (child != null && search(word.substring(i + 1), child)) {
return true;
}
}
return false;
}
node = node.children[idx];
}
return node.isEnd;
}
}
/**
* Your WordDictionary object will be instantiated and called as such:
* WordDictionary obj = new WordDictionary();
* obj.addWord(word);
* boolean param_2 = obj.search(word);
*/
class trie {
public:
vector<trie*> children;
bool is_end;
trie() {
children = vector<trie*>(26, nullptr);
is_end = false;
}
void insert(const string& word) {
trie* cur = this;
for (char c : word) {
c -= 'a';
if (cur->children[c] == nullptr) {
cur->children[c] = new trie;
}
cur = cur->children[c];
}
cur->is_end = true;
}
};
class WordDictionary {
private:
trie* root;
public:
WordDictionary()
: root(new trie) {}
void addWord(string word) {
root->insert(word);
}
bool search(string word) {
return dfs(word, 0, root);
}
private:
bool dfs(const string& word, int i, trie* cur) {
if (i == word.size()) {
return cur->is_end;
}
char c = word[i];
if (c != '.') {
trie* child = cur->children[c - 'a'];
if (child != nullptr && dfs(word, i + 1, child)) {
return true;
}
} else {
for (trie* child : cur->children) {
if (child != nullptr && dfs(word, i + 1, child)) {
return true;
}
}
}
return false;
}
};
/**
* Your WordDictionary object will be instantiated and called as such:
* WordDictionary* obj = new WordDictionary();
* obj->addWord(word);
* bool param_2 = obj->search(word);
*/
type WordDictionary struct {
root *trie
}
func Constructor() WordDictionary {
return WordDictionary{new(trie)}
}
func (this *WordDictionary) AddWord(word string) {
this.root.insert(word)
}
func (this *WordDictionary) Search(word string) bool {
n := len(word)
var dfs func(int, *trie) bool
dfs = func(i int, cur *trie) bool {
if i == n {
return cur.isEnd
}
c := word[i]
if c != '.' {
child := cur.children[c-'a']
if child != nil && dfs(i+1, child) {
return true
}
} else {
for _, child := range cur.children {
if child != nil && dfs(i+1, child) {
return true
}
}
}
return false
}
return dfs(0, this.root)
}
type trie struct {
children [26]*trie
isEnd bool
}
func (t *trie) insert(word string) {
cur := t
for _, c := range word {
c -= 'a'
if cur.children[c] == nil {
cur.children[c] = new(trie)
}
cur = cur.children[c]
}
cur.isEnd = true
}
/**
* Your WordDictionary object will be instantiated and called as such:
* obj := Constructor();
* obj.AddWord(word);
* param_2 := obj.Search(word);
*/
using System.Collections.Generic;
using System.Linq;
class TrieNode {
public bool IsEnd { get; set; }
public TrieNode[] Children { get; set; }
public TrieNode() {
Children = new TrieNode[26];
}
}
public class WordDictionary {
private TrieNode root;
public WordDictionary() {
root = new TrieNode();
}
public void AddWord(string word) {
var node = root;
for (var i = 0; i < word.Length; ++i)
{
TrieNode nextNode;
var index = word[i] - 'a';
nextNode = node.Children[index];
if (nextNode == null)
{
nextNode = new TrieNode();
node.Children[index] = nextNode;
}
node = nextNode;
}
node.IsEnd = true;
}
public bool Search(string word) {
var queue = new Queue<TrieNode>();
queue.Enqueue(root);
for (var i = 0; i < word.Length; ++i)
{
var count = queue.Count;
while (count-- > 0)
{
var node = queue.Dequeue();
if (word[i] == '.')
{
foreach (var nextNode in node.Children)
{
if (nextNode != null)
{
queue.Enqueue(nextNode);
}
}
}
else
{
var nextNode = node.Children[word[i] - 'a'];
if (nextNode != null)
{
queue.Enqueue(nextNode);
}
}
}
}
return queue.Any(n => n.IsEnd);
}
}