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answering to my own question, it would add as delayed job after experimenting with sample code. |
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@manast
I have a question on failed Jobs. lets say I use backoff exponential and attempts = 5. Now my job failed. The question is, does bullmq actually reput the Job with
delay= 2^(attempts-1) * retry timeout
and creates a delayed job to retry again in future, orthe same worker which got the error will actually wait for delay seconds (like sleep in the same worker for delay seconds) and then try again.
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