Creating a multiple URL vCard using vObject

[meet-VC]

How can I get multiple URL in one VCard.

I want to create a VCard with details like:

• Fname
• Lname
• Company name
• Phone number
• address
• website url
• facebook url
• insta gram url
• Tik tok url
• twitter url

I tried the following code

	vCard.add('URL')
	vCard.url.value = 'https://www.example.com'
	vCard.url.type_param = "Website:"

	vCard.add('URL')
	vCard.url.value = 'https://www.facebook.com'
	vCard.url.type_param = "Facebook:"

In the output I was only able to get one of the link:

BEGIN:VCARD
VERSION:3.0
EMAIL;TYPE=INTERNET:[email protected]
FN:Justin
N:White;Justin;;;
ORG:Tesla
TEL;TYPE=HOME:+16503977339
URL;TYPE=Facebook:https://www.facebook.com
URL:
END:VCARD

[brandon-clair]

@meet-VC You'll have to construct an initial "URL" component, and then manually append additional children to the component list, which is hinted at in the readme.

Similar to parameters, If you want to access more than just the first child of a Component, you can access the full list of children of a given name by appending _list to the attribute name:

Since "URL" components don't have a constructor class (as opposed to "N", which has vobject.vcard.Name()), you'll also have to manually build the children you want to append with vobject.base.ContentLine(). The ContentLine docstring is misleading when it states that its params argument is a dictionary. It actually requires a list of lists.

Here's how I made multiple URLs:

>>> import vobject
>>> card = vobject.vCard()
>>> card.add('n')
<N{}    >
>>> card.add('fn')
<FN{}>
>>> card.add('url')
<URL{}>
>>> card.url.value = 'https://www.example.com'
>>> card.url.type_param = 'Website:'
>>> card.url_list.append(vobject.base.ContentLine('URL', [['TYPE:','Facebook:']], 'https://www.facebook.com'))
>>> card.serialize()
'BEGIN:VCARD\r\nVERSION:3.0\r\nFN:\r\nN:;;;;\r\nURL;TYPE="Website:":https://www.example.com\r\nURL;TYPE:="Facebook:":https://www.facebook.com\r\nEND:VCARD\r\n'