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https://www.v2ex.com/t/1050084 目标: A 队和 B 队各 10 人排队(轮流)攻打一个怪兽,谁最后一下打死怪兽,掉落物品就属于哪个队。 规则:攻打有两种方式,一种就是正常打,每人打一下。另外一种是队伍集结攻打,5 人合起来打一下,能打出 6 人的战力。不管怎么打,“打一下”都是串行的,可以认为是排队。两种攻打方式可以自由组合。 问题:怎么打怪兽得到掉落物品的概率高一下?
The text was updated successfully, but these errors were encountered:
目标的措辞改一下:
A 队和 B 队各 10 人同时攻打一个怪兽 -> A 队和 B 队各 10 人排队攻打一个怪兽
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感觉这道题主要是博弈论相关的,如果通过概率论的角度解需要更多数值上的建模。
不过从目前来看,假设存在这么一个策略S使得拿到装备的概率更高,那么对手同样可以用策略S来攻击,这时候没有其他设定的情况下两队的概率应该是接近均等的。
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