forked from shuboc/LeetCode-2
-
Notifications
You must be signed in to change notification settings - Fork 0
/
string-to-integer-atoi.py
67 lines (60 loc) · 2.38 KB
/
string-to-integer-atoi.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
# Time: O(n)
# Space: O(1)
#
# Implement atoi to convert a string to an integer.
#
# Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below
# and ask yourself what are the possible input cases.
#
# Notes: It is intended for this problem to be specified vaguely (ie, no given input specs).
# You are responsible to gather all the input requirements up front.
#
# spoilers alert... click to show requirements for atoi.
#
# Requirements for atoi:
# The function first discards as many whitespace characters as necessary
# until the first non-whitespace character is found. Then, starting from this character,
# takes an optional initial plus or minus sign followed by as many numerical digits as possible, and interprets them as a numerical value.
#
# The string can contain additional characters after those that
# form the integral number, which are ignored and have no effect on the behavior of this function.
#
# If the first sequence of non-whitespace characters in str is not a valid integral number,
# or if no such sequence exists because either str is empty or it contains only whitespace characters, no conversion is performed.
#
# If no valid conversion could be performed, a zero value is returned.
# If the correct value is out of the range of representable values, INT_MAX (2147483647) or INT_MIN (-2147483648) is returned.
#
class Solution(object):
def myAtoi(self, str):
"""
:type str: str
:rtype: int
"""
INT_MAX = 2147483647
INT_MIN = -2147483648
result = 0
if not str:
return result
i = 0
while i < len(str) and str[i] == " ":
i += 1
sign = 1
if str[i] == "+":
i += 1
elif str[i] == "-":
sign = -1
i += 1
while i < len(str) and str[i] >= '0' and str[i] <= '9':
if result > (INT_MAX - (ord(str[i]) - ord('0'))) / 10:
return INT_MAX if sign > 0 else INT_MIN
result = result * 10 + ord(str[i]) - ord('0')
i += 1
return sign * result
if __name__ == "__main__":
print Solution().atoi("")
print Solution().atoi("-1")
print Solution().atoi("2147483647")
print Solution().atoi("2147483648")
print Solution().atoi("-2147483648")
print Solution().atoi("-2147483649")