forked from Divya063/LeetCode
-
Notifications
You must be signed in to change notification settings - Fork 0
/
water-and-jug-problem.py
42 lines (39 loc) · 1.08 KB
/
water-and-jug-problem.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
# Time: O(logn), n is the max of (x, y)
# Space: O(1)
# You are given two jugs with capacities x and y litres.
# There is an infinite amount of water supply available.
# You need to determine whether it is possible to
# measure exactly z litres using these two jugs.
#
# Operations allowed:
#
# Fill any of the jugs completely.
# Empty any of the jugs.
# Pour water from one jug into another till
# the other jug is completely full or
# the first jug itself is empty.
# Example 1:
#
# Input: x = 2, y = 6, z = 4
# Output: True
# Example 2:
#
# Input: x = 2, y = 6, z = 5
# Output: False
# Bézout's identity (also called Bézout's lemma)
class Solution(object):
def canMeasureWater(self, x, y, z):
"""
:type x: int
:type y: int
:type z: int
:rtype: bool
"""
def gcd(a, b):
while b:
a, b = b, a%b
return a
# The problem is to solve:
# - check z <= x + y
# - check if there is any (a, b) integers s.t. ax + by = z
return z == 0 or ((z <= x + y) and (z % gcd(x, y) == 0))