forked from Divya063/LeetCode
-
Notifications
You must be signed in to change notification settings - Fork 0
/
rotate-list.py
53 lines (45 loc) · 1.18 KB
/
rotate-list.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
from __future__ import print_function
# Time: O(n)
# Space: O(1)
#
# Given a list, rotate the list to the right by k places, where k is non-negative.
#
# For example:
# Given 1->2->3->4->5->NULL and k = 2,
# return 4->5->1->2->3->NULL.
#
# Definition for singly-linked list.
class ListNode:
def __init__(self, x):
self.val = x
self.next = None
def __repr__(self):
if self:
return "{} -> {}".format(self.val, repr(self.next))
class Solution(object):
def rotateRight(self, head, k):
"""
:type head: ListNode
:type k: int
:rtype: ListNode
"""
if not head or not head.next:
return head
n, cur = 1, head
while cur.next:
cur = cur.next
n += 1
cur.next = head
cur, tail = head, cur
for _ in xrange(n - k % n):
tail = cur
cur = cur.next
tail.next = None
return cur
if __name__ == "__main__":
head = ListNode(1)
head.next = ListNode(2)
head.next.next = ListNode(3)
head.next.next.next = ListNode(4)
head.next.next.next.next = ListNode(5)
print(Solution().rotateRight(head, 2))