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implement-magic-dictionary.py
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implement-magic-dictionary.py
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# Time: O(n), n is the length of the word
# Space: O(d)
# Implement a magic directory with buildDict, and search methods.
#
# For the method buildDict, you'll be given a list of non-repetitive words to build a dictionary.
#
# For the method search, you'll be given a word, and judge whether
# if you modify exactly one character into another character in this word,
# the modified word is in the dictionary you just built.
#
# Example 1:
# Input: buildDict(["hello", "leetcode"]), Output: Null
# Input: search("hello"), Output: False
# Input: search("hhllo"), Output: True
# Input: search("hell"), Output: False
# Input: search("leetcoded"), Output: False
# Note:
# You may assume that all the inputs are consist of lowercase letters a-z.
# For contest purpose, the test data is rather small by now.
# You could think about highly efficient algorithm after the contest.
# Please remember to RESET your class variables declared in class MagicDictionary,
# as static/class variables are persisted across multiple test cases. Please see here for more details.
import collections
class MagicDictionary(object):
def __init__(self):
"""
Initialize your data structure here.
"""
_trie = lambda: collections.defaultdict(_trie)
self.trie = _trie()
def buildDict(self, dictionary):
"""
Build a dictionary through a list of words
:type dictionary: List[str]
:rtype: void
"""
for word in dictionary:
reduce(dict.__getitem__, word, self.trie).setdefault("_end")
def search(self, word):
"""
Returns if there is any word in the trie that equals to the given word after modifying exactly one character
:type word: str
:rtype: bool
"""
def find(word, curr, i, mistakeAllowed):
if i == len(word):
return "_end" in curr and not mistakeAllowed
if word[i] not in curr:
return any(find(word, curr[c], i+1, False) for c in curr if c != "_end") \
if mistakeAllowed else False
if mistakeAllowed:
return find(word, curr[word[i]], i+1, True) or \
any(find(word, curr[c], i+1, False) \
for c in curr if c not in ("_end", word[i]))
return find(word, curr[word[i]], i+1, False)
return find(word, self.trie, 0, True)
# Your MagicDictionary object will be instantiated and called as such:
# obj = MagicDictionary()
# obj.buildDict(dict)
# param_2 = obj.search(word)