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So no additional isNaN( x ) || isFinite( x ) checks are needed, isFinite( x ) is sufficient.
isNaN( x ) || isFinite( x )
isFinite( x )
Review: #31
The text was updated successfully, but these errors were encountered:
Fixed via 6a0430b. Reassign to @jonathanolson for verification.
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jonathanolson
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So no additional
isNaN( x ) || isFinite( x )
checks are needed,isFinite( x )
is sufficient.Review: #31
The text was updated successfully, but these errors were encountered: