forked from keon/algorithms
-
Notifications
You must be signed in to change notification settings - Fork 5
/
decode_string.py
44 lines (36 loc) · 1.27 KB
/
decode_string.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
# Given an encoded string, return it's decoded string.
# The encoding rule is: k[encoded_string], where the encoded_string
# inside the square brackets is being repeated exactly k times.
# Note that k is guaranteed to be a positive integer.
# You may assume that the input string is always valid; No extra white spaces,
# square brackets are well-formed, etc.
# Furthermore, you may assume that the original data does not contain any
# digits and that digits are only for those repeat numbers, k.
# For example, there won't be input like 3a or 2[4].
# Examples:
# s = "3[a]2[bc]", return "aaabcbc".
# s = "3[a2[c]]", return "accaccacc".
# s = "2[abc]3[cd]ef", return "abcabccdcdcdef".
def decode_string(s):
"""
:type s: str
:rtype: str
"""
stack = []; cur_num = 0; cur_string = ''
for c in s:
if c == '[':
stack.append((cur_string, cur_num))
cur_string = ''
cur_num = 0
elif c == ']':
prev_string, num = stack.pop()
cur_string = prev_string + num * cur_string
elif c.isdigit():
cur_num = cur_num*10 + int(c)
else:
cur_string += c
return cur_string
a = "3[a]2[bc]" #"aaabcbc".
b = "3[a2[c]]" #"accaccacc".
print(decode_string(a))
print(decode_string(b))