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Hope to add a method for calculating the hypotenuse with three parameters : double double.Hypot(double, double, double), Equivalent to Math.Sqrt(x * x + y * y + z * z), Simplified double.Hypot(double.Hypot(x, y), z)
The text was updated successfully, but these errors were encountered:
Hope to add a method for calculating the hypotenuse with three parameters : double double.Hypot(double, double, double), Equivalent to Math.Sqrt(x * x + y * y + z * z), Simplified double.Hypot(double.Hypot(x, y), z)
The text was updated successfully, but these errors were encountered: