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isMeasurable requires pointed type #796
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Dear Shin-ya Katsumata, you are completely right this definition alters the categorical properties of measurable spaces as types. This choice was made to have (partial) inverses for functions |
NB: If one change pointed to choice in analysis/theories/lebesgue_integral.v Line 262 in f421377
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Ha! This is really funny, because : |
Why does the |
Observation by @t6s : it should be easy to insert an intermediate mixin for non-necessarily not-trivial rings once MathComp 2.0 is available. |
Sorry I forgot to answer. Guillaume Cano added the intermediate structure in mathcomp 1, ten years ago, but it was never merged because of the huge impact it had on the library. Adding this structure is actually one of the reasons of existence of HB and mathcomp 2. |
Hi, I am Shin-ya Katsumata at NII, invited to this project by Reynald.
I have a question: it appears that the measurable space whose carrier is the empty set (type) seems excluded from the definition, because isMeasurable requires a pointed type. I wonder why.
The standard definition of measurable space includes the empty one. Also, categorically, excluding the empty measurable space drastically changes the property of the category of measurable spaces.
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