-
Notifications
You must be signed in to change notification settings - Fork 0
/
24.py
executable file
·48 lines (32 loc) · 1.08 KB
/
24.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
#! /usr/bin/env python
# A permutation is an ordered arrangement of objects.
# For example, 3124 is one possible permutation of the digits 1, 2, 3 and 4.
# If all of the permutations are listed numerically or alphabetically, we call it lexicographic order.
# The lexicographic permutations of 0, 1 and 2 are:
#
# 012 021 102 120 201 210
#
# What is the millionth lexicographic permutation of the digits 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9?
def permutations(n):
counts = [1] * (n + 1)
for i in range(n + 1):
counts[i] -= 1
for perm in helper([i], counts):
yield perm
counts[i] += 1
def helper(permutation, counts):
if sum(counts) == 0:
yield ''.join(map(str, permutation))
return
for i in range(len(counts)):
if counts[i] != 0:
counts[i] -= 1
permutation.append(i)
for perm in helper(permutation, counts):
yield perm
counts[i] += 1
permutation.pop()
perms = permutations(9)
for x in range(999999):
perms.next()
print perms.next()