A beginner level CTF challenge
Question 1: c4n y0u c4p7u23 7h3 f149?
This is called leet speak, the text is written with modified spellings with numbers
We have: can you capture the flag?
Question 2:
01101100 01100101 01110100 01110011 00100000 01110100 01110010 01111001 00100000 01110011 01101111 01101101 01100101 00100000 01100010 01101001 01101110 01100001 01110010 01111001 00100000 01101111 01110101 01110100 00100001
What is the series of 1's and 0's? This is binary, the "language of computers"
Question 3: MJQXGZJTGIQGS4ZAON2XAZLSEBRW63LNN5XCA2LOEBBVIRRHOM======
Having an equal sign at the end of the string, it's base32 or base64.
In our case, we have base32 decoder
Question 4: RWFjaCBCYXNlNjQgZGlnaXQgcmVwcmVzZW50cyBleGFjdGx5IDYgYml0cyBvZiBkYXRhLg==
And this is in form of base64
Question 5: 68 65 78 61 64 65 63 69 6d 61 6c 20 6f 72 20 62 61 73 65 31 36 3f
The existence of numbers and characters lower than f points into the direction of hexadecimal
Question 6: Ebgngr zr 13 cynprf!
You can see in the answer, the form of the character is the same as in the question.
This ensures that this is a single transform character cipher, it's ROT13
ROT13 is an extremely simple cipher where each letter in a phrase is "rotated" 13 times
Question 7: *@F DA:? >6 C:89E C@F?5 323J C:89E C@F?5 Wcf E:>6DX
This is somewhat similar to the previous one. It's ROT47 cipher
But instead of using just the letters A-Z, it uses all characters in the ASCII encoding table
Question 8: — . .-.. . -.-. — — — — ..- -. .. -.-. .- — .. — — -. . -. -.-. — — -.. .. -. — .
If you had an enough experience in forensics, telecomunicate or watch film, you will know it's morse code
Dots and dashes are used in morse code.
Question 9: 85 110 112 97 99 107 32 116 104 105 115 32 66 67 68
This sequence of numbers could have been decimal or octal. So i tried with base10
It's decimal form
Question 10:
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Li0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLi0tLS0KLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLi0tLS0KLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLS0tLS0gLi0tLS0gLi0tLS0gLi0tLS0gLi0tLS0gLi0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLS0tLS0gLi0tLS0gLi0tLS0gLi0tLS0gLi0tLS0gLi0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0KLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLS0tLS0gLi0tLS0gLi0tLS0gLi0tLS0gLi0tLS0gLi0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLS0tLS0gLi0tLS0gLi0tLS0gLi0tLS0gLi0tLS0gLi0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLi0tLS0KLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLi0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLi0tLS0KLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLi0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLi0tLS0KLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLS0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLi0tLS0KLS0tLS0gLi0tLS0gLi0tLS0gLS0tLS0gLS0tLS0gLi0tLS0gLS0tLS0gLi0tLS0=
At first, you will see this question quite confusing with a lot of LS0 and Li0t characters
But notice the equal sign at the end, it's base64
Decode the base64, we have a morse code
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Converted the morse code, we have
011001100110010100100000011000000101111101100000001000000110000001100000011001010010000001100010011010000010000001100000011000000110010000100000011000100110000100100000011000000101111101101000001000000110100001100110001000000110000001011111011001100010000001100000010111110110000000100000011000100110000100100000011000000110000001100101001000000110000001011111011000110010000001100000010111110110010000100000011000000110000001100100001000000110001001100001001000000110100001100110001000000110001001100001001000000110100001100111001000000110000001011111011001000010000001100000011000000110010100100000011000100110000100100000011000000110000001100101001000000110000001100000011000110010000001100000010111110110010000100000011010000110100000100000011000000101111101100110001000000110000001011111011001000010000001100000010111110110000000100000011000000110000001100011001000000110001101100101001000000110001101100101001000000110001101100101
decode the binary:
fe `_` ``e bh ``d ba `_h hf `_f `_` ba ``e `_c `_d ``d ba hf ba hg `_d ``e ba ``e ``c `_d hh `_f `_d `_` ``c ce ce ce
hmm, at this step i think the hint in our previous question, it's rot47
76 101 116 39 115 32 109 97 107 101 32 116 104 105 115 32 97 32 98 105 116 32 116 114 105 99 107 105 101 114 46 46 46
then convert from decimal, we have Let's make this a bit trickier...
Answer:
A spectrogram is a visual representation of the spectrum of frequencies of a signal as it varies with time.
When applied to an audio signal, spectrograms are sometimes called sonographs, voiceprints, or voicegrams.
When the data is represented in a 3D plot they may be called waterfalls.
Using Audacity, i have the answer
Steganography is the practice of concealing a file, message, image, or video within another file, message, image, or video.
or you can use steghide –extract -sf stegosteg.jpg
the question say that download the file and check it's extension, so it's not a normal image
i tried with strings command or open with notepad
that's very clear that 2 flags in our view
or you can use binwalk –extract meme.jpg
The principle here can be simply understood as a compressed file containing image content and another file
Of course, information that can be read in plain text will be displayed when using strings.