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numSpecialEquivGroups.py
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numSpecialEquivGroups.py
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'''
Source : https://leetcode.com/problems/groups-of-special-equivalent-strings/
Author : Yuan Wang
Date : 2019-01-08
/**********************************************************************************
*You are given an array A of strings.
*
*Two strings S and T are special-equivalent if after any number of moves, S == T.
*
*A move consists of choosing two indices i and j with i % 2 == j % 2, and swapping
*S[i] with S[j].
*
*Now, a group of special-equivalent strings from A is a non-empty subset S of A such
*that any string not in S is not special-equivalent with any string in S.
*
*Return the number of groups of special-equivalent strings from A.
Example 1:
Input: ["a","b","c","a","c","c"]
Output: 3
Explanation: 3 groups ["a","a"], ["b"], ["c","c","c"]
Example 2:
Input: ["aa","bb","ab","ba"]
Output: 4
Explanation: 4 groups ["aa"], ["bb"], ["ab"], ["ba"]
**********************************************************************************/
'''
def numSpecialEquivGroups(A):
"""
:type A: List[str]
:rtype: int
"""
def count(A):
ans = [0] * 52
for i, letter in enumerate(A):
ans[ord(letter) - ord('a') + 26 * (i%2)] += 1
return tuple(ans)
return len({count(word) for word in A})
import unittest
class Test(unittest.TestCase):
def setUp(self):
self.A = ["a","b","c","a","c","c"]
self.B = ["aa","bb","ab","ba"]
def test(self):
self.assertEqual(numSpecialEquivGroups(self.A),3)
self.assertEqual(numSpecialEquivGroups(self.B),4)
if __name__ == '__main__':
unittest.main()