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class Solution {
public:
vector<string> findWords(vector<string>& words) {
vector<string> res;
unordered_set<char> row1{'q','w','e','r','t','y','u','i','o','p'};
unordered_set<char> row2{'a','s','d','f','g','h','j','k','l'};
unordered_set<char> row3{'z','x','c','v','b','n','m'};
for (string word : words) {
int one = 0, two = 0, three = 0;
for (char c : word) {
if (c < 'a') c += 32;
if (row1.count(c)) one = 1;
if (row2.count(c)) two = 1;
if (row3.count(c)) three = 1;
if (one + two + three > 1) break;
}
if (one + two + three == 1) res.push_back(word);
}
return res;
}
};
Given a List of words, return the words that can be typed using letters of alphabet on only one row's of American keyboard like the image below.
Example 1:
Note:
这道题给了我们一些单词,问哪些单词可以由键盘上的一行中的键符打出来,难度其实并不大。首先我们把键盘的三行字符分别保存到三个set中,然后遍历每个单词中的每个字符,分别看当前字符是否在三个集合中,如果在,对应的标识变量变为1,我们统计三个标识变量之和就知道有几个集合参与其中了,参见代码如下:
参考资料:
https://discuss.leetcode.com/topic/77754/java-1-line-solution-via-regex-and-stream
LeetCode All in One 题目讲解汇总(持续更新中...)
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