You are given a string s
of lowercase English letters and a 2D integer array shifts
where shifts[i] = [starti, endi, directioni]
. For every i
, shift the characters in s
from the index starti
to the index endi
(inclusive) forward if directioni = 1
, or shift the characters backward if directioni = 0
.
Shifting a character forward means replacing it with the next letter in the alphabet (wrapping around so that 'z'
becomes 'a'
). Similarly, shifting a character backward means replacing it with the previous letter in the alphabet (wrapping around so that 'a'
becomes 'z'
).
Return the final string after all such shifts to s
are applied.
Input: s = "abc", shifts = [[0,1,0],[1,2,1],[0,2,1]] Output: "ace" Explanation: Firstly, shift the characters from index 0 to index 1 backward. Now s = "zac". Secondly, shift the characters from index 1 to index 2 forward. Now s = "zbd". Finally, shift the characters from index 0 to index 2 forward. Now s = "ace".
Input: s = "dztz", shifts = [[0,0,0],[1,1,1]] Output: "catz" Explanation: Firstly, shift the characters from index 0 to index 0 backward. Now s = "cztz". Finally, shift the characters from index 1 to index 1 forward. Now s = "catz".
1 <= s.length, shifts.length <= 5 * 104
shifts[i].length == 3
0 <= starti <= endi < s.length
0 <= directioni <= 1
s
consists of lowercase English letters.
impl Solution {
pub fn shifting_letters(s: String, shifts: Vec<Vec<i32>>) -> String {
let mut s = s.into_bytes();
let mut prefix_sum = vec![0; s.len()];
for i in 0..shifts.len() {
if shifts[i][0] > 0 {
prefix_sum[shifts[i][0] as usize - 1] -= 2 * shifts[i][2] - 1;
}
prefix_sum[shifts[i][1] as usize] += 2 * shifts[i][2] - 1;
}
for i in (0..prefix_sum.len()).rev() {
prefix_sum[i] += *prefix_sum.get(i + 1).unwrap_or(&0);
s[i] = ((s[i] - b'a') as i32 + prefix_sum[i]).rem_euclid(26) as u8 + b'a';
}
String::from_utf8(s).unwrap()
}
}