Given the root
node of a binary search tree, return the sum of values of all nodes with value between L
and R
(inclusive).
The binary search tree is guaranteed to have unique values.
Input: root = [10,5,15,3,7,null,18], L = 7, R = 15 Output: 32
Input: root = [10,5,15,3,7,13,18,1,null,6], L = 6, R = 10 Output: 23
- The number of nodes in the tree is at most
10000
. - The final answer is guaranteed to be less than
231
.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def rangeSumBST(self, root: TreeNode, L: int, R: int) -> int:
rangesum = root.val
if rangesum < L or rangesum > R:
rangesum = 0
if root.left:
rangesum += self.rangeSumBST(root.left, L, R)
if root.right:
rangesum += self.rangeSumBST(root.right, L, R)
return rangesum