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Hard
Database

1972. First and Last Call On the Same Day 🔒

中文文档

Description

Table: Calls

+--------------+----------+
| Column Name  | Type     |
+--------------+----------+
| caller_id    | int      |
| recipient_id | int      |
| call_time    | datetime |
+--------------+----------+
(caller_id, recipient_id, call_time) is the primary key (combination of columns with unique values) for this table.
Each row contains information about the time of a phone call between caller_id and recipient_id.

 

Write a solution to report the IDs of the users whose first and last calls on any day were with the same person. Calls are counted regardless of being the caller or the recipient.

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Calls table:
+-----------+--------------+---------------------+
| caller_id | recipient_id | call_time           |
+-----------+--------------+---------------------+
| 8         | 4            | 2021-08-24 17:46:07 |
| 4         | 8            | 2021-08-24 19:57:13 |
| 5         | 1            | 2021-08-11 05:28:44 |
| 8         | 3            | 2021-08-17 04:04:15 |
| 11        | 3            | 2021-08-17 13:07:00 |
| 8         | 11           | 2021-08-17 22:22:22 |
+-----------+--------------+---------------------+
Output: 
+---------+
| user_id |
+---------+
| 1       |
| 4       |
| 5       |
| 8       |
+---------+
Explanation: 
On 2021-08-24, the first and last call of this day for user 8 was with user 4. User 8 should be included in the answer.
Similarly, user 4 on 2021-08-24 had their first and last call with user 8. User 4 should be included in the answer.
On 2021-08-11, user 1 and 5 had a call. This call was the only call for both of them on this day. Since this call is the first and last call of the day for both of them, they should both be included in the answer.

Solutions

Solution 1

MySQL

# Write your MySQL query statement below
with s as (
    select
        *
    from
        Calls
    union
    all
    select
        recipient_id,
        caller_id,
        call_time
    from
        Calls
),
t as (
    select
        caller_id user_id,
        FIRST_VALUE(recipient_id) over(
            partition by DATE_FORMAT(call_time, '%Y-%m-%d'),
            caller_id
            order by
                call_time asc
        ) first,
        FIRST_VALUE(recipient_id) over(
            partition by DATE_FORMAT(call_time, '%Y-%m-%d'),
            caller_id
            order by
                call_time desc
        ) last
    from
        s
)
select
    distinct user_id
from
    t
where
    first = last