README_EN.md

comments	difficulty	edit_url	tags
true	Easy	https://github.com/doocs/leetcode/edit/main/solution/1800-1899/1821.Find%20Customers%20With%20Positive%20Revenue%20this%20Year/README_EN.md	Database

1821. Find Customers With Positive Revenue this Year 🔒

中文文档

Description

Table: Customers

+--------------+------+
| Column Name  | Type |
+--------------+------+
| customer_id  | int  |
| year         | int  |
| revenue      | int  |
+--------------+------+
(customer_id, year) is the primary key (combination of columns with unique values) for this table.
This table contains the customer ID and the revenue of customers in different years.
Note that this revenue can be negative.

 

Write a solution to report the customers with postive revenue in the year 2021.

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Customers table:
+-------------+------+---------+
| customer_id | year | revenue |
+-------------+------+---------+
| 1           | 2018 | 50      |
| 1           | 2021 | 30      |
| 1           | 2020 | 70      |
| 2           | 2021 | -50     |
| 3           | 2018 | 10      |
| 3           | 2016 | 50      |
| 4           | 2021 | 20      |
+-------------+------+---------+
Output: 
+-------------+
| customer_id |
+-------------+
| 1           |
| 4           |
+-------------+
Explanation: 
Customer 1 has revenue equal to 30 in the year 2021.
Customer 2 has revenue equal to -50 in the year 2021.
Customer 3 has no revenue in the year 2021.
Customer 4 has revenue equal to 20 in the year 2021.
Thus only customers 1 and 4 have positive revenue in the year 2021.

Solutions

Solution 1: WHERE Clause

We can directly use the WHERE clause to filter out the customers whose year is 2021 and revenue is greater than $0$.

MySQL

# Write your MySQL query statement below
SELECT
    customer_id
FROM Customers
WHERE year = '2021' AND revenue > 0;