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Hard
Database

1225. Report Contiguous Dates 🔒

中文文档

Description

Table: Failed

+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| fail_date    | date    |
+--------------+---------+
fail_date is the primary key (column with unique values) for this table.
This table contains the days of failed tasks.

 

Table: Succeeded

+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| success_date | date    |
+--------------+---------+
success_date is the primary key (column with unique values) for this table.
This table contains the days of succeeded tasks.

 

A system is running one task every day. Every task is independent of the previous tasks. The tasks can fail or succeed.

Write a solution to report the period_state for each continuous interval of days in the period from 2019-01-01 to 2019-12-31.

period_state is 'failed' if tasks in this interval failed or 'succeeded' if tasks in this interval succeeded. Interval of days are retrieved as start_date and end_date.

Return the result table ordered by start_date.

The result format is in the following example.

 

Example 1:

Input: 
Failed table:
+-------------------+
| fail_date         |
+-------------------+
| 2018-12-28        |
| 2018-12-29        |
| 2019-01-04        |
| 2019-01-05        |
+-------------------+
Succeeded table:
+-------------------+
| success_date      |
+-------------------+
| 2018-12-30        |
| 2018-12-31        |
| 2019-01-01        |
| 2019-01-02        |
| 2019-01-03        |
| 2019-01-06        |
+-------------------+
Output: 
+--------------+--------------+--------------+
| period_state | start_date   | end_date     |
+--------------+--------------+--------------+
| succeeded    | 2019-01-01   | 2019-01-03   |
| failed       | 2019-01-04   | 2019-01-05   |
| succeeded    | 2019-01-06   | 2019-01-06   |
+--------------+--------------+--------------+
Explanation: 
The report ignored the system state in 2018 as we care about the system in the period 2019-01-01 to 2019-12-31.
From 2019-01-01 to 2019-01-03 all tasks succeeded and the system state was "succeeded".
From 2019-01-04 to 2019-01-05 all tasks failed and the system state was "failed".
From 2019-01-06 to 2019-01-06 all tasks succeeded and the system state was "succeeded".

Solutions

Solution 1: Union + Window Function + Group By

We can merge the two tables into one table with a field st representing the status, where failed indicates failure and succeeded indicates success. Then, we can use a window function to group the records with the same status into one group, and calculate the difference between each date and its rank within the group as pt, which serves as the identifier for the same continuous status. Finally, we can group by st and pt, and calculate the minimum and maximum dates for each group, and sort by the minimum date.

MySQL

# Write your MySQL query statement below
WITH
    T AS (
        SELECT fail_date AS dt, 'failed' AS st
        FROM Failed
        WHERE YEAR(fail_date) = 2019
        UNION ALL
        SELECT success_date AS dt, 'succeeded' AS st
        FROM Succeeded
        WHERE YEAR(success_date) = 2019
    )
SELECT
    st AS period_state,
    MIN(dt) AS start_date,
    MAX(dt) AS end_date
FROM
    (
        SELECT
            *,
            SUBDATE(
                dt,
                RANK() OVER (
                    PARTITION BY st
                    ORDER BY dt
                )
            ) AS pt
        FROM T
    ) AS t
GROUP BY 1, pt
ORDER BY 2;