Wait the job ends before starts again

[dudumiquim]

I'm looking for a method to schedule a job to run every 2 seconds but without to start another thread while the first one is running yet.
I read the FAQ and the issues but no one comment about it.

import threading
import time
import schedule

def job():
    print("A: %s"  % threading.get_ident(), time.time())
    time.sleep(3)
    print("B: %s"  % threading.get_ident(), time.time())
    
def run_threaded(job_func):
    job_thread = threading.Thread(target=job_func)
    job_thread.start()

schedule.every(2).seconds.do(run_threaded, job)

while 1:
    schedule.run_pending()
    time.sleep(1)

The output is:

A: 139822667417344 1524702860
A: 139822659024640 1524702862
B: 139822667417344 1524702863
A: 139822667417344 1524702864
B: 139822659024640 1524702865
A: 139822659024640 1524702866
B: 139822667417344 1524702867
A: 139822667417344 1524702868

But, I would like something like it:

A: 139822667417344 1524702860
B: 139822667417344 1524702863
A: 139822667417344 1524702865
B: 139822667417344 1524702868

The every(2) start to count after the job ends.

[gkovacs81]

I think this should solve your problem:
...
job_thread.start()
job_thread.join()
...

My question is: how to wait for the threaded jobs in the main process to finish after a keyboard interrupt?