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When running normalizeEmail on email addresses that contain a quoted @ in the user part (which is legal and correctly identified by isEmail), it will return an invalid email address.
When running
normalizeEmail
on email addresses that contain a quoted@
in the user part (which is legal and correctly identified byisEmail
), it will return an invalid email address.Expected output for the last two lines:
I would advise splitting the email in this fashion instead of assuming that a
.split('@')
would return an array of length 2:The text was updated successfully, but these errors were encountered: