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Parse OverloadedLabels #394
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One tricky part is this case - example = foo & (#bar . #baz) .~ 'z' Clearly we want to parse both Also, as an aside, the example expression can also be written this way, avoiding the problem - example = foo & #bar . #baz .~ 'z' However, this is clearly no solution and we still need to think about how to handle it. |
This is not valid syntax with
You would need to write the expression like so: example = foo & ( #bar . #baz ) .~ 'z' |
Yes, but if UnboxedTuples is not enabled, it should work. Having the IntelliJ lexer change what is a lexeme based on language extensions will be tricky. |
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